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3 years ago

write an equation that represents the following sentence? the sum of a number and two is twice the number.

Mathematics

1 answer:

Bogdan [553]3 years ago

5 0

The sum of a number and 2
x + 2
is twice the number
2x
answer
<span>x + 2 = 2x</span>

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Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9

faust18 [17]

Answer:

-5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

-5 with multiplicity 3
+9 with multiplicity 2
-1

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2 years ago

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

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2 years ago

The tip jar at a sandwich shop has been found to have a dollar value 0.65ℎ +1.25, where ℎ is the number of hours since the shop

DedPeter [7]

Answer:

The intial value is 1.25

Step-by-step explanation:

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3 years ago

10|x+8| - 13 = -2|x+8|+11

PilotLPTM [1.2K]

Use the app Socratic

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2 years ago

Neo could choose from 3 different pants, 5 different shirts, and 4 sweaters. How many different combinations of 1 pant, 1 shirt

Sidana [21]

To answer you do 5 times 4 times 3 to get 60

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3 years ago