Answer:
a. radius = 0.0006m = 0.6mm and length =0.393m = 393mm
b. frequency =377.86Hz
Explanation:
Given:
mass of steel= 4g = 0.004kg
density of steel = 7890kg/m3
tensile stress of steel 7.0x10⁸
tension load =900N
from the density, we will calculate for the Volume of the steel string
density = mass/volume
volume = mass/density = 0.004/7890 = 5.07 x 10⁻⁷ m³
from the tensile stress will can get the maximum base Area of the string ,
tensile stress = load/area =
7x10⁸ = 900/A
A = 900/7x10⁸ = 1.29x10⁻⁶ m²
Area = πr²
area/pi = 4.105x10-7
radius = 0.0006m = 0.6mm
volume = Area x length
length = vol/area =(5.07 x 10⁻⁷ m³)/1.29x10⁻⁶ m² = 0.393m
b. the highest possible frequency is given by:
F = 
where T= tension, m=mass, L=length
F = 
= 297.04/0.786
frequency =377.86Hz
Answer:
Purchases= 408,000 pounds
Explanation:
Giving the following information:
Production:
2nd Q= 99,000 units
3rd= 109,000 units
Four pounds of material A are required for each unit produced.
Desired ending inventory= 30% of the next quarter's production
<u>To calculate the purchases for the second quarter, we need to use the following formula:</u>
Purchases= production + desired ending inventory - beginning inventory
Purchases= (99,000*4) + (109,000*4)*0.3 - (99,000*4)*0.3
Purchases= 396,000 + 130,800 - 118,800
Purchases= 408,000 pounds
Answer:
1. Particulars Super premium Premium Economy
Material cost $16 $12 $10
Indirect cost (40000/10000) <u>$4 </u> <u>$4 </u> <u>$4</u>
Total cost $20 $16 $14
Profit (100% of total cost) <u>$20 </u> <u>$16 </u> <u>$14</u>
Selling price <u>$40</u> <u>$32 </u> <u>$28</u>
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2. Yes, the price calculated in part A takes into account what customers are willing to pay. This can be said because the company has the policy of adding 100% to the total cost. This means that the company knows that customers will be willing to pay that much amount.
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