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NemiM [27]
3 years ago
15

the length of a rectangle is 7 inches more than its width, if the perimiter of the rectangle is 66 inches, find its dimensions.

Mathematics
1 answer:
Maurinko [17]3 years ago
3 0
Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w

if the length is 7in more than the width, then
L=7+w

Now we will substitute 7+w in for L. Here is our new equation:

66=2(7+w) + 2w

Solve for w

66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20

I hooe this is explained well enough
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A random sample of 20 purchases showed the amounts in the table (in $). The mean is $49.57 and the standard deviation is $20.28.
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The 98​% confidence interval for the mean purchases of all​ customers is ($37.40, $61.74).

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M = 2.325*\frac{20.28}{\sqrt{20}} = 12.17

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a_sh-v [17]

Answer with explanation:

The given mathematical expression to solve : 35+50

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=5(7+10)=5(17)=85

3 0
3 years ago
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