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NemiM [27]
4 years ago
15

the length of a rectangle is 7 inches more than its width, if the perimiter of the rectangle is 66 inches, find its dimensions.

Mathematics
1 answer:
Maurinko [17]4 years ago
3 0
Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w

if the length is 7in more than the width, then
L=7+w

Now we will substitute 7+w in for L. Here is our new equation:

66=2(7+w) + 2w

Solve for w

66=14+2w+2w
66=14+4w
52=4w
w=13
L=7+13, so L=20

I hooe this is explained well enough
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Equation: f(z)=20+5z

Step-by-step explanation:

Given,

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Let,

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y be the initial value.

According to given statement;

6x+y=50.00    Eqn 1

12x+y=80.00   Eqn 2

Subtracting Eqn 2 from Eqn 1

(12x+y)-(6x+y)=80.00-50.00\\12x+y-6x-y=30.00\\6x=30.00

Dividing both sides by 6

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Putting in Eqn 1;

6(5.00)+y=50.00\\30.00+y=50.00\\y=50.00-30.00\\y=20.00

The constant rate for 1 floral arrangement is $5.00 and inital value is $20.00

Equation for the function;

Let z be the number of floral arrangements.

f(z) = initial fee + 5*Number of floral arrangements

f(z) = 20+5z

Keywords: function, subtraction

Learn more about functions at:

  • brainly.com/question/4695279
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