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3 years ago

NO PLAGARISM

1 answer:

7 0

Answer: It depends on the concentration of all solutes in the solution (ie, its osmolarity). A solution with low osmolarity is hypotonic and vice versa. Solutions having the same osmolarity are isotonic. Water in pools and rivers is hypotonic compared with sea water, but water from the Dead Sea is hypertonic.We do not swell and pop when we go swimming in a hypotonic swimming pool because our skin protects us from the external environment and does not let water cross into or out of our body surfaces. ... hope this helps have a great day

Explanation:

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How much heat energy would be released if 78.1 g of water at 0.00 °c were converted to ice at −57.1 °c. give your answer as a po

kolezko [41]

To convert 78.1 g of water at 0° C to Ice at -57.1°C; we can do it in steps;
1. Water at 0°C to ice at 0°C
The heat of fusion of ice is 334 J/g;
Heat = 78.1 × 334 = 26085.4 Joules
2. Ice at 0°C to -57.1°C
Specific heat of ice is 2.108 J/g
Heat = 78.1 × 2.108 J/g = 164.6348 Joules
Thus the total heat energy released will be; 26085.4 + 164.6348
= 26250.0348 J or 26.250 kJ

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

If 0.0106 g of a gas dissolves in 0.792 L of water at 0.321 atm, what quantity of this gas (in grams) will dissolve at 5.73 atm?

Alex73 [517]

Answer:

0.189 g.

Explanation:

This problem is an application on Henry's law.

Henry's law states that the solubility of a gas in a liquid is directly proportional to its partial pressure of the gas above the liquid.

Solubility of the gas ∝ partial pressure

If we have different solubility at different pressures, we can express Henry's law as:

S₁/P₁ = S₂/P₂,

S₁ = 0.0106/0.792 = 0.0134 g/L and P₁ = 0.321 atm

S₂ = ??? g/L and P₂ = 5.73 atm

So, The solubility of the gas at 5.73 atm (S₂) = S₁.P₂/P₁ = (0.0134 g/L x 5.73 atm) / (0.321 atm) = 0.239 g/L.

The quantity in (g) = S₂ x V = (0.239 g/L)(0.792 L) = 0.189 g.

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3 years ago

If a sample of gas is located 10.2 cm from the injection point and the chart speed is 0.5 cm/min, what is the retention time?

Archy [21]

Answer : The retention time is, 20 min

Explanation :

Retention time : It is defined as the amount of time a compound spends on the column after it has been injected.

Formula of retention time is:

$\text{Retention time}=\frac{\text{Distance from injection point to center of peaks}}{\text{Chart recorded speed}}$

Given:

Distance from injection point to center of peaks = 10 cm

Chart recorded speed = 0.5 cm/min

Now put all the given values in the above formula, we get:

$\text{Retention time}=\frac{10cm}{0.5cm/min}$

Retention time = 20 min

Thus, the retention time is, 20 min

3 0

4 years ago