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andrew11 [14]
3 years ago
9

What is the mass (in grams) of 9.83 × 1024 molecules of methanol (CH3OH)?

Chemistry
1 answer:
Ber [7]3 years ago
5 0
<span>523 grams First, calculate the molar mass of CH3OH Atomic weight of carbon = 12.0107 Atomic weight of hydrogen = 1.00794 Atomic weight of oxygen = 15.999 Molar mass of CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 Now determine how many moles you have by dividing the number of atoms by avogadro's number moles = 9.83 x 10^24 / 6.0221409 x 10^23 = 16.3231 Now multiply the number of moles by the molar mass 16.3231 * 32.04146 = 523.0159557 Since we only have 3 significant figures, round the result to 3 significant figures. 523.0159557 grams = 523 grams</span>
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If 0.896 g of a gas occupies a 250 mL flask at 20°C and 760 mm Hg of pressure, what is the molar mass of the gas?​
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86.2 g/mol

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Before you can find the molar mass, you first need to calculate the number of moles of the gas. To find this value, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (mmHg)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas constant (62.36 L*mmHg/mol*K)

-----> T = temperature (K)

After you convert the volume from mL to L and the temperature from Celsius to Kelvin, you can use the equation to find the moles.

P = 760 mmHg                                      R = 62.36 L*mmHg/mol*K

V = 250 mL / 1,000 = 0.250 L              T = 20 °C + 273.15 = 293.15 K

n = ? moles

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(760 mmHg)(0.250 L) = n(62.36 L*mmHg/mol*K)(293.15 K)

190 = n(18280.834)

0.0104 = n

The molar mass represents the mass (g) of the gas per every 1 mole. Since you have been given a mass and mole value, you can set up a proportion to determine the molar mass.

\frac{?grams}{1 mole} =\frac{0.896grams}{0.0104moles}                                      <----- Proportion

?grams(0.0104moles) = 0.896                       <----- Cross-multiply

?grams = 86.2                                               <----- Divide both sides by 0.0104

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