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andrew11 [14]
3 years ago
9

What is the mass (in grams) of 9.83 × 1024 molecules of methanol (CH3OH)?

Chemistry
1 answer:
Ber [7]3 years ago
5 0
<span>523 grams First, calculate the molar mass of CH3OH Atomic weight of carbon = 12.0107 Atomic weight of hydrogen = 1.00794 Atomic weight of oxygen = 15.999 Molar mass of CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 Now determine how many moles you have by dividing the number of atoms by avogadro's number moles = 9.83 x 10^24 / 6.0221409 x 10^23 = 16.3231 Now multiply the number of moles by the molar mass 16.3231 * 32.04146 = 523.0159557 Since we only have 3 significant figures, round the result to 3 significant figures. 523.0159557 grams = 523 grams</span>
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3. Determine the moles of sodium, Na, containing 7.9x1024 atoms.​
-BARSIC- [3]

Answer:

12.7mol Na.

Explanation:

Hello there!

In this case, according to the concept of mole, which stands for the amount of substance, we can recall the concept of Avogadro's number whereby we understand that one mole of any substance contains 6.022x10²³ particles, for the given atoms of sodium, we can calculate the moles as shown below:

7.9x10^{23}atoms*\frac{1mol}{6.022x10^{23}atoms} \\\\

Thus, by performing the division we obtain:

12.7molNa

Regards!

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<h3>What is the keto-enol means in tautomer?</h3>

They carries a carbonyl bond even as enol implies the presence of a double bond and a hydroxyl group. The keto-enol tautomerization equilibrium is depending on stabilization elements of each the keto tautomer and the enol tautomer.

  1. The enol that could provide 2-pentanone might had been pent-1- en - 2 -ol. Because an equilibrium favors the ketone so greatly, equilibrium isn't an excellent description.
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  3. If a catalyst have been delivered, NaOH for example, then formation of the enolate of pent-1-en - 2 - ol might shape and react with bromine.
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