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Snowcat [4.5K]
3 years ago
14

Using the perioduc table determine the mass of one mole in the element carbon​

Chemistry
1 answer:
weeeeeb [17]3 years ago
8 0

One mole of carbon atoms has a mass of exactly 12 g. Because magnesium atoms each have twice the mass of carbon atoms (24Mg compared with 12C), one mole of magnesium has a mass of 24 g. In fact, one mole of any element has a mass in grams that is equal to its relative atomic mass. One mole of iron has a mass of 56 g

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Help! ill give brainliest
ArbitrLikvidat [17]

Answer:

Option B

Explanation:

Magnesium is an alkali earth metal and chlorine is a nonmetal. Due to this, and their differences in electronegativity, the elements form an ionic bond. Since magnesium has two valence electrons, it will give them up to two chlorine atoms (which has 7 valence electrons), which needs them to complete its octet. From this, magnesium forms a cation, and will have the ion formula Mg(2+). The two chlorine atoms form anions, and will have the ion formula Cl(1-).

Terms:

  • Cation: a positively charged ion
  • Anion: a negatively charge ion.
  • Electronegativity: the tendency of an atom in a molecule to attract the shared pair of electrons towards itself.
7 0
2 years ago
Read 2 more answers
For an ideal gas, evaluate the volume occupied by 0.3 mole of gas.
Serhud [2]

Answer:

V=0.3×22.4=6.72 liters hope this helps

8 0
2 years ago
Where is ocean water the densest?
Vika [28.1K]

Answer:

your answer should be the bottom

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Explanation:

8 0
2 years ago
A substance with a pH of 4.0?
IrinaVladis [17]
Tomato juice or acid rain
7 0
3 years ago
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What are the missing coefficents for the following equation? __N2+__H2->__NH3
vivado [14]

Answer:

1, 3, 2

Explanation:

N2 + H2 → NH3

I usually find that the best way to systematically balance an equation by inspection is to start with the most complicated-looking formula and then balance atoms in the order:

  1. All atoms other than O and H
  2. O
  3. H

(a) The most complicated formula is NH3.

(b) Balance N.

We have 1 H in NH3, but 2 N on the left. We need 2 N on the right. Put a 1 in front of N2 and a 2 in front of NH3.

1N2 + H2 → 2NH3

(c) Balance H.

We have fixed 6 H on the right, so we need 6 H on the left. Put a 3 in front of H2.

1N2 + 3H2 → 2NH3

The equation is now balanced, and the coefficients are 1, 3, 2.

5 0
2 years ago
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