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amid [387]
3 years ago
10

Write 1/4 as a fraction with 8 as the denominator. Then add the fraction to 3/8. What is the sum? Write the fractions and the an

swer.
Mathematics
1 answer:
a_sh-v [17]3 years ago
3 0

Answer:

2/8, 5/8

Step-by-step explanation:

\frac{1}{4}*\frac{2}{2} =\frac{2}{8} \\\\\frac{3}{8} +\frac{2}{8} =\frac{5}{8}

Multiplying by 2/2 is like multiplying by 1, so it doesn't affect the value.

To add fractions with the same denominator just add the numerator, the denominator stays the same.

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When you want to use a discount membership to save money you are required to purchase a membership. A popular place that people often purchase memberships from are Costco or Sam's Club.
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Help please!!!<br> What is P(0.6 ≤ z ≤ 2.12)?<br> 16% <br> 26% <br> 73% <br> 98%
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PLEASE HELP!!!!<br>how to solve 9x^3-16x^2=0 by factoring<br> WILL GIVE BRAINLIEST IF CORRECT!!!!
andreev551 [17]

Answer:

x=5.3

Step-by-step explanation:

Graph each side of the equation. The solution is the x-value of the point of intersection.

x

≈

5.3

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7 0
3 years ago
Cosx+1/sin^3x=cscx/1-cosx
ANTONII [103]
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).

 </span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).

 </span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.

 </span>
<span>I hope this helps! </span>
8 0
4 years ago
If there are 6 serving in a 2/3 pound lb package of pound is in each serving
Serhud [2]

Answer:

\boxed{\math{\frac{1}{9}\text{ lb}}}

Step-by-step explanation:

\text{Size of one serving} = \dfrac{\text{Total size}}{\text{No of servings}} = \dfrac{\frac{2}{3}\text{ lb}}{\text{6 servings}}\\\\\text{Change the 6 to a fraction and change divide to multiply}\\\\\dfrac{2}{3} \div 6 = \dfrac{2}{3} \times \dfrac{1}{6}

\text{Cancel the 2s}\\\\\dfrac{2}{3} \times \dfrac{1}{6} = \dfrac{1}{3} \times \dfrac{1}{3}\\\\\text{Multiply numerators and denominators}\\\\\dfrac{1}{3} \times \dfrac{1}{3} = \dfrac{1}{9}\\\\\text{Each serving contains }\boxed{\mathbf{\frac{1}{9}\textbf{ lb}}}

3 0
3 years ago
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