7, 14 would be it but you have to divide the whole equation by 2 to get the y alone
Answer:
The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Step-by-step explanation:
In a random sample of 300 boards the number of boards that fall outside the specification is 12.
Compute the sample proportion of boards that fall outside the specification in this sample as follows:
The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:
The critical value of <em>z</em> for 95% confidence level is,
*Use a <em>z</em>-table.
Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:
Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).
Answer:
10 guests a table
Step-by-step explanation:
3 tables
7 late arrivals
37 total people
37 minus 7 is 30
30 divided by 3 is 10
answer is 10
9/20 is greater
9/20 = 0.45
..............