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Contact [7]
2 years ago
15

Use the interactive number line to help complete each exercise. Place points at -1 and -4. Complete the inequality: -1 -4. Place

points at the opposites for each number. Which inequality statement is true?
Mathematics
2 answers:
77julia77 [94]2 years ago
5 0

Answer:

1.>

2.1 < 4

Step-by-step explanation

Sliva [168]2 years ago
4 0

Question might not be complete

Answer and explanation:

The signs -1 and -4 lie on the negative side of the number line, left of zero(positive right of zero).

The opposites for each number would be +1 and +4 which would all be on the right side of zero on the number line

Inequality signs or statements to represent greater and lesser number on the number line using the numbers above as examples would be:

-1<+1

-4<-1

+1>-1

+1<4

-1-4<1+4

Numbers that don't have signs attached to them are automatically positive numbers

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If f is a continuous function such that the integral from 1 to 4 of f of x, dx equals 10, evaluate the integral from 2 to 8 of 2
IgorLugansk [536]

Answer: 10

Step-by-step explanation:

Since integral from 1 to 4 of f(x) =10

To evaluate integral from 2 to 8 of 2 times f(2x), using substitution method

Let U = 2x, dU = 2dx, dx = dU/2

Evaluate the limit, upper limit gives dU = 2*4 = 8, lower limit gives dU = 2*1 = 2.

Since this limit are the same as the limit for the question,

Therefore, F(4) - F(1) = F(8) - F(2) = 10

Substituting dx=dU/2

Gives,

Integral from 2 to 8 of 2 times f(2x)= (1/2)(2)(F(8)-F(2)) = 10

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3 years ago
10. When a rubber ball is dropped from a height, h cm on to a flat concrete floor, it rebounds to 3 5 h cm a height of Given a r
Xelga [282]

Step-by-step explanation:

Let the height above which the ball is released be H

This problem can be tackled using geometric progression.

The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is

To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H

a=2H..........r=3/4

However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H

Therefore the total distance travel up to the Nth bounce is

For N=3 one obtains

D=3.625H

7 0
2 years ago
Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple rando
cupoosta [38]

Answer:

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

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2 years ago
solomon has read 1/3 of his book. He finishes the book by reading the same amount eat night for 5 nights what fraction of the bo
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3 years ago
Find the area each sector. Do Not round. Part 1. NO LINKS!!<br><br>​
sladkih [1.3K]

Answer:

\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2

\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta

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\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2

19)  Given:

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\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2

21)  Given:

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\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2

23)  Given:

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\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2

3 0
2 years ago
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