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aleksklad [387]
3 years ago
7

Find the measure of ∠AED for m∠BEC = 118

Mathematics
1 answer:
mylen [45]3 years ago
7 0

dang nobody answered.. and this question is on an assignment  

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9 × 2(3 + 5) – (10 × 12) = y
vagabundo [1.1K]
The answer is y=24 your welcome
5 0
2 years ago
If m∠JKM = 43, m∠MKL = (8 - 20), and m∠JKL = (10x - 11), find each measure.
Brut [27]

Correct Question: If m∠JKM = 43, m∠MKL = (8x - 20), and m∠JKL = (10x - 11), find each measure.

1. x = ?

2. m∠MKL = ?

3. m∠JKL = ?

Answer/Step-by-step explanation:

Given:

m<JKM = 43,

m<MKL = (8x - 20),

m<JKL = (10x - 11).

Required:

1. Value of x

2. m<MKL

3. m<JKL

Solution:

1. Value of x:

m<JKL = m<MKL + m<JKM (angle addition postulate)

Therefore:

(10x - 11) = (8x - 20) + 43

Solve for x

10x - 11 = 8x - 20 + 43

10x - 11 = 8x + 23

Subtract 8x from both sides

10x - 11 - 8x = 8x + 23 - 8x

2x - 11 = 23

Add 11 to both sides

2x - 11 + 11 = 23 + 11

2x = 34

Divide both sides by 2

\frac{2x}{2} = \frac{34}{2}

x = 17

2. m<MKL = 8x - 20

Plug in the value of x

m<MKL = 8(17) - 20 = 136 - 20 = 116°

3. m<JKL = 10x - 11

m<JKL = 10(17) - 11 = 170 - 11 = 159°

3 0
2 years ago
NEED HELP!!!!! NOT IN A RUSH THOUGH
nexus9112 [7]

gvgdyefuriiyuugujyyuy you

6 0
3 years ago
Please help me! I really need to pass this !! : (
Vlada [557]

A=49.44

B=232.91

C=-283.29

(49.44-232.91)+(-283.29)=-466.76

-283-(232.91+49.44)=-565.35

3 0
2 years ago
Read 2 more answers
6(p+3)-6(p+5) expand and simplify need help asap
Alex Ar [27]

Step-by-step explanation:

6(p+3)-6(p+5)=6p+18-6p-30=-12

8 0
3 years ago
Read 2 more answers
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