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aleksklad [387]
3 years ago
7

Find the measure of ∠AED for m∠BEC = 118

Mathematics
1 answer:
mylen [45]3 years ago
7 0

dang nobody answered.. and this question is on an assignment  

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Write and solve an equation to find the unknown side length x (in inches).
Gekata [30.6K]

The value of side length x is equal 6.05 in

<h3>Perimeter of a Square</h3>

The perimeter of a square is given as the sum of the total sides in the square or 4 multiplied by the side length of the square since they all have equal sides.

Mathematically, this can be written as

P = 4 *L\\P = 4l\\

  • L = side length

In this given question, the side length is equal to x and the perimeter of the square is given as 24.2in.

Let's substitute the values

P = 4L\\24.2 = 4L\\but l = x\\24.2 = 4x\\x = 6.05in

The side length of the square is equal to 6.05in

Learn more on perimeter of square here;

brainly.com/question/24487155

#SPJ1

complete question

Write and solve an equation to find the unknown side length x (in inches).

Perimeter =24.2 in. assuming the figure is a square

8 0
1 year ago
Graph the function y=2-VX+1. What is the missing x-coordinate for the point (x,- 1.24), to the nearest tenth?
alex41 [277]
8.4 dhndyshshsjsjs yup that’s it’s 778 it indicates
5 0
3 years ago
Read 2 more answers
Y=-5x+3 in standard form
vazorg [7]
Standard form =
ax + by = c

y = -5x + 3
Add 5x to both sides.

5x + y = 3
And this is your answer.
6 0
3 years ago
(-11x^2 +6) - (14x^2 +2)
Nataly [62]

Answer:

−1(5−2)(5+2)

Step-by-step explanation:

Eliminate redundant parentheses

(−11²+6)−1(14² +2)

Distribute

−11² + 6 -- 1(14² +2)

−11² + 6 - 14² − 2

8 0
3 years ago
The diagram shows the entrance to a tunnel.
gladu [14]

Step-by-step explanation:

it filled up half the circle (up to the center point) - if we had a full circle. but a little bit is cut off (below AB).

what we see is that the shaded area is the sum of the area of the triangle AOB and 2 equally sized circle segment areas left and right of AOB.

since we are dealing with a half-circle, we have 180° in total. 120° are taken by AOB, so, that leaves us with 180-120 = 60° for both circle segments (so, one has an angle of 30°).

and 2×30° = 1×60°, so we can calculate the area of one 60° segment instead of two 30° segments.

AOB is an isoceles triangle (the legs are equally long, and therefore also the 2 side angles are equal).

the area of this triangle AOB is

1/2 × a × b × sin(C) = 1/2 × 3 × 3 × sin(120) =

= 3.897114317... m²

a circle segment area of 60° is 60/360 = 1/6 of the full circle area (as a full circle = 360°).

so, it's area is

pi×r² × 1/6 = pi×3²/6 = pi×3/2 = 4.71238898... m²

so, the total area of the shaded area is

3.897114317... m² + 4.71238898... m² =

= 8.609503297... m²

5 0
3 years ago
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