The smallest of two integers is 61
Step-by-step explanation:
Let x be the smaller integer
Then the next integer will be:
x+1
According to given statement that the sum of both is 123

Subtracting 1 from both sides

Dividing both sides by 2

The smallest of two integers is 61
Keywords: Linear equations, Variables
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Answer:
Area of the rhombus ABCD = 16 square units
Step-by-step explanation:
Area of a rhombus = 
From the graph attached,
Diagonal 1 = Distance between the points A and C
Diagonal 2 = Distance between the points B and D
Length of a segment between (x₁, y₁) and (x₂, y₂) = 
Diagonal 1 (AC) =
= 4 units
Diagonal 2(BD) =
= 8 units
Now area of the rhombus ABCD = 
= 
= 16 units²
Therefore, area of the given rhombus is 16 units².
A and C could be the answer
Answer:
80%
Step-by-step explanation:
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