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Slav-nsk [51]
3 years ago
15

Can you check my paper? If I got any wrong please tell me the correct answers.

Mathematics
1 answer:
djyliett [7]3 years ago
3 0

There is a lot to go over here. Unfortunately it looks like you got a lot incorrect. I'll focus on two problems. Hopefully these examples below will help correct the other mistakes.

---------------------------------------------------------

Problem 7)

We have the starting value be 20 and the ending value be 11. Subtract the values: (end)-(start) = 11 - 20 = -9. The negative indicates we have a drop or decrease.

We'll focus on the positive version of this number, so 9. Divide this value over the starting amount 20 to get 9/20 = 0.45 = 45%

So going from 20 miles to 11 miles is a decrease of 45%

Answer to problem 7 is: 45%

---------------------------------------------------------

Problem 13)

An increase of 300% means we added 3 times the original amount onto the original amount.

We take 300% of 25 to get 3*25 = 75

Which is then added onto 25 to get 25+75 = 100

Answer to problem 13 is: 100

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The basic metric unit of capacity is a liter. :)
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3 years ago
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The electrical charge on a metal plate is given
Katarina [22]

Answer:

after 10 seconds  the charge  is 1.624

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one.

The electrical charge on a metal plate is given  by the function below, where t is the time in  seconds. What is the charge after 10 seconds?

C (t) = 12e^{\frac{-t}{5} }

My answer:

Given the information:

C (t) = 12e^{\frac{-t}{5} }  

when t =10 we have:

C (10) = 12e^{\frac{-10}{5} }

<=>  C (10) = 12e^{-2}

<=>  C (10) = 12\frac{1}{e^{2} }

<=> C (10) = 12 * 0.1353

<=>  C (10) = 1.624

Hence, after 10 seconds  the charge  is 1.624

8 0
2 years ago
The product of 2 consecutive #s is 4160 what are the numbers?
KengaRu [80]
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x(x+1)=4160
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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

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3 years ago
What is 2 thirds of 60
Mkey [24]
You have to set up a proportion so 2 over 3= x over 60. So multiply 2 times 60= 120 divided by 3 which is 40
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