Answer (Note: the bold are answers):
First question answer:
Point = (3,1)
Slope = 3
y = 3x + b
(1) = 3(3) + b
1 = 9 + b
1 - 9 = b
-8 = b
y = 3x - 8
The second question answer:
y = mx + b
Get two points:
(3,-7) and (4,-11)
m = -11 - (-7) / 4 - 3
m = -11 + 7 / 1
m = -4 / 1
m = -4
b = + 3
y = -4x + 3
Answer:
x^2 + 18x + 76 + 5 = 0 + 5
Step-by-step explanation:
The first step is to determine the constant that is needed to be able to write the expression in the desired form. That constant is the square of half the x-term coefficient: (18/2)^2 = 9^2 = 81.
The constant that is present is 76, which is 5 fewer than the needed constant, so the "first step" is to add 5 to both sides of the equation:
x^2 + 18x + 76 + 5 = 0 + 5
Then the next step would be to write the left side as a square:
(x +9)^2 = 5 . . . . . . . p = -9; q= 5
Two lines that cross each other have each pair of angles the same.
2x+6=96 --> x=45
Answer:
Step-by-step explanation:
(2,1), (-2,-1)
slope(m) = (-1-1) / (-2 - 2) = -2/-4 = 1/2
parallel lines will have the same slope
y = mx + b
slope(m) = 1/2
(-4,8)...x = -4 and y = 8
now sub and find b, the y int
8 = 1/2(-4) + b
8 = -2 + b
8 + 2 = b
10 = b
so ur equation is : y = 1/2x + 10 <==
Answer:
6, 9
Step-by-step explanation:
y1-y2 over x1-x2
slope formula ^^
