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vovikov84 [41]
4 years ago
6

4. Solve this equation for x. Please show work. 4√x + 3 + 3 = 15​

Mathematics
1 answer:
tresset_1 [31]4 years ago
5 0

Answer:

i don't know sorry b a b y g i r l

Step-by-step explanation:

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Solve by factoring.<br><br> 3q^2+q-14=0
hodyreva [135]
When doing this equation, draw a big X on your paper. At the top of the x you do A times C. At the bottom, you put the B. To factor, you need to find what two numbers MULTIPLY together to equal the A times C, and that add together to get the B.

In all you will get (q+7) (q-6)
3 0
4 years ago
Hi, help:/<br> Thank you
erma4kov [3.2K]

Answer:

its the first on 5,3 can you give me brainliest

Step-by-step explanation:

3 0
3 years ago
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Can angles 4 &amp; 8 be proven parallel?​
myrzilka [38]

Answer:

No

Step-by-step explanation:

5 0
3 years ago
What are the limits of integration if the summation the limit as n goes to infinity of the summation from k equals 1 to n of the
Fofino [41]

Answer:

\int_{2}^{9}x^2 dx so the limits are 2 and 9

Step-by-step explanation:

We want to express \lim_{n\rightarrow \infty} \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a integral. To do this, we have to identify \sum_{k=1}^n\frac{7}{n}(2+\frac{7k}{n})^2 as a Riemann Sum that approximates the integral. (taking the limit makes the approximation equal to the value of the integral)

In general, to find a Riemann sum that approximates the integral of a function f over an interval [a,b] we can the interval in n subintervals of equal length and approximate the area (integral) with rectangles in each subinterval and them sum the areas. This is equal to

\sum_{k=1}^n f(y_k) \frac{b-a}{n}, where y_k\in[a+(k-1)\frac{b-a}{n},a+k\frac{b-a}{n}] is a selected point of the subinterval.

In particular, if we select the ending point of each subinterval as the y_k, the Riemann sum is:

\sum_{k=1}^n f(a+k\frac{b-a}{n}) \frac{b-a}{n}.

Now, let's identify this in \sum_{k=1}^n\frac{1}{7n}(2+\frac{7k}{n})^2 .

The integrand is x² so this is our function f. When k=n, the summand should be \frac{b-a}{n}f(b)=\frac{b-a}{n}b^2 because the last selected point is b. The last summand is \frac{7}{n}(9)^2 thus b=9 and b-a=7, then 9-a=7 which implies that a=2.

To verify our answer, note that if we substitute a=2, b=9 and f(x)=x² in the general Riemann Sum, we obtain the sum inside the limit as required.

4 0
3 years ago
I need help asap!!!
lara [203]

Answer: 12

Step-by-step explanation:

You would take 3+5=8

And then 20-8=12

7 0
3 years ago
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