Answer: sin
= ± 
Step-by-step explanation:
We very well know that,
cos2A=1−2sin²A
⟹ sinA = ±
As required, set A = & cos a= 
,thus we get
sin =± 
∴ sin =±
= ±
since ,360° < <450°
,180° < <225°
Now, we are to select the value with the correct sign. It's is obvious from the above constraints that the angle a/2 lies in the III-quadrant where 'sine' has negative value, thus the required value is negative.
hope it helped!
Answer: 81 units²
Step-by-step explanation: To solve this problem, remember that the formula for the area of a square is 4s.
Therefore, since the perimeter of the given square is 36, we have 36 = 4s and dividing both sides by 4, 9 = s.
Now, remember that the formula for the area of a square is s² and since the length of a side of the given square is 9, we have (9)² or 81.
So the area of a square that has a perimeter of 36 is 81 units².
well the absolute means positive so it would be a positive 1.6
I think u do 3•5 then divide by 110
