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Nikolay [14]
3 years ago
12

What is the answer of the problem; 3x-4+2(x-5)=9x+8-2x

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

Step-by-step explanation:

Given problem is 3x-4+2(x-5)=9x+8-2x

To solve the equation:

3x-4+2(x-5)=9x+8-2x

3x-4+2x-10=9x+8-2x  (multiplying the term with factor)

5x-4-10=7x+8  (adding the like terms)

5x-14=7x+8  (adding the like terms)

Now taking the terms to one side

5x-14-7x-8=0

-2x-22=0 (adding the like terms)

-2x=22

-x=\frac{22}{2}

-x=11

x=-11

Therefore x=-11

The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

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Sphinxa [80]

Answer:

{24, 18, 12, 6, 0} is the range of the above function

Step-by-step explanation:

solution:

let, x= -4

f(-2) = 12-3*(-2)

= 12+12

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let,x= -2

f(-2) = 12-3*(-2)

=12+6

18

let,x =0

f(0)= 12-3*0

=12-0

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let,x=2

f(2) = 12-3*2

=12-6

=6

let,x=4

f(4) = 12-3*4

=12-12

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4 0
3 years ago
You have 42,784 grams of a radioactive kind of curium. If its half-life is 18 years, how much will be left after 72 years?
s344n2d4d5 [400]

Answer:

2,674.14 g

Step-by-step explanation:

Recall that the formula for radioactive decay is

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where,

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λ = coefficient of radioactive decay

  = 0.693 ÷ Half Life

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t = time elapsed (given as 72 years)

e = exponential constant ( approx 2.7183)

If we substitute these into our equation:

N = N₀ e^(-λt)

= (42,787) (2.7183)^[(-0.0385)(72)]

= (42,787) (2.7183)^(-2.7726)

=  (42,787) (0.0625)

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6 0
3 years ago
The first five terms of an arithmetic sequence are shown below: 20, 17, 14, 11, 8, . . . Let n represent the term number and f(n
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Answer: 17 -3n

Explanation:

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let n is the nth term

a_{n} = a+(n-1)d

substituting the values of first, common,difference and n

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6 0
3 years ago
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Answer:

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y = 2

Therefore, the equation of the graphed line is:

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