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Nikolay [14]
3 years ago
12

What is the answer of the problem; 3x-4+2(x-5)=9x+8-2x

Mathematics
1 answer:
alexgriva [62]3 years ago
5 0

Answer:

The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

Step-by-step explanation:

Given problem is 3x-4+2(x-5)=9x+8-2x

To solve the equation:

3x-4+2(x-5)=9x+8-2x

3x-4+2x-10=9x+8-2x  (multiplying the term with factor)

5x-4-10=7x+8  (adding the like terms)

5x-14=7x+8  (adding the like terms)

Now taking the terms to one side

5x-14-7x-8=0

-2x-22=0 (adding the like terms)

-2x=22

-x=\frac{22}{2}

-x=11

x=-11

Therefore x=-11

The answer to the given problem 3x-4+2(x-5)=9x+8-2x is x=-11

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A wire that is 22 feet long connects the top of a pole to the ground. The wire is attached to the ground at a point that is 10 f
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✰ <u>Concept</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

In this question, we can clearly observer that the diagram shows a right angled triangle. And, we have been provided with the value of base, and the value of hypotenuse, using the pythagoras theorem, now we can easily find out the value of the perpendicular i.e. the value of the side h. According to the pythagoras theorem, square of hypotenuse is equal to the sum of square of perpendicular and square of side respectively. Therefore, square of side is equal to the difference of square of hypotenuse and square of perpendicular.

⠀

✰ <u>Given</u><u> </u><u>Information</u><u> </u>:-

⠀

  • Hypotenuse = 22 ft.
  • Base = 10 ft.

⠀

✰ <u>To Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The value of side or the perpendicular

⠀

✰ <u>Formula</u><u> </u><u>Used</u><u> </u><u>:</u><u>-</u>

⠀

\star \:  \underline{ \boxed{ \purple { \sf  {Side}^{2}  =  {Hypotenuse}^{2}  -  {Base}^{2}  }}} \:  \star

⠀

✰ <u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

\sf \longrightarrow  {Side}^{2} =   {(22 \: ft)}^{2}  -  {(10 \: ft)}^{2}  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{2} =   {484 \: ft}^{2}  -  {100 \: ft}^{2}  \:  \:  \: \:  \:  \:   \\  \\  \\ \sf \longrightarrow  {Side}^{2} =   {384 \: ft}^{2}  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{} =   \sqrt{ {384 \: ft}^{2} }  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\ \sf \longrightarrow  {Side}^{} =   \underline{ \boxed{ \frak{ \green{19.60 \: ft}}}} \:  \star \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\

Thus, option B. 19.60 ft. is the correct option.

⠀

\underline{\rule{230pt}{2pt}} \\  \\

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