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nekit [7.7K]
3 years ago
5

What is the solution to the equation below? 3x + 29.5 = - 75.5

Mathematics
1 answer:
son4ous [18]3 years ago
8 0

Answer:

x = − 35

Step-by-step explanation:

hope this helps

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Here so u can give that person brainliest

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How are corresponding side lengths of two similar figures related?
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If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal.

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Choose correct way to write three dollars and seventeen cents using the dollar symbol.
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3 years ago
About 11% of adult Americans are left-handed. Suppose that two people are randomly selected from this
marshall27 [118]

Answer:

a) P(X=0)=(2C0)(0.11)^0 (1-0.11)^{2-0}=0.7921  

P(X=1)=(2C1)(0.11)^1 (1-0.11)^{2-1}=0.1958  

P(X=2)=(2C2)(0.11)^2 (1-0.11)^{2-2}=0.0121  

And then we have our probability distribution like this:

X     |       0    |      1     |     2    |

P(X) |  0.7921 | 0.1958 | 0.0121|

b) P(X \geq 1) = P(X=1)+P(X=2) = 0.1958+0.0121=0.2079

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=20, p=0.48)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Solution for the problem

Part a

On this case since we select a sample size of n =2 we have the following values for the number of left handed X=0,1,2. We can find the probabilities for each case since we know that p=0.11.

P(X=0)=(2C0)(0.11)^0 (1-0.11)^{2-0}=0.7921  

P(X=1)=(2C1)(0.11)^1 (1-0.11)^{2-1}=0.1958  

P(X=2)=(2C2)(0.11)^2 (1-0.11)^{2-2}=0.0121  

And then we have our probability distribution like this:

X     |       0    |      1     |     2    |

P(X) |  0.7921 | 0.1958 | 0.0121|

Part b

For this case we want this probability:

P(X \geq 1) = P(X=1)+P(X=2) = 0.1958+0.0121=0.2079

8 0
3 years ago
Solve for x: 3 over 3 x plus 1 over quantity x plus 4 equals 10 over 7x. (2 points)
riadik2000 [5.3K]
Let me see if I can decipher that :P

3/(3x)+1/x+4=10/(7x)  first we need to make all terms have a common denominator of 21x...

(21+21+84x)/(21x)=30/(21x)  multiplying both sides by 21x leaves you with

21+21+84x=30  combine like terms on left side

42+84x=30  subtract 42 from both sides

84x=-12  divide both sides by 84

x=-1/7
5 0
3 years ago
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