Question

Here is a rule to make a list of numbers: Each number is 4 less than 3 times the previous number. starting with the number 1, build a sequence of 5 number

Answer 1

the sequence of 5 numbers for the given rule and inital number is:

{1, -1, - 7, -25, -79}

How to find the first 5 numbers in the given sequence?

A sequence is a list of numbers in order, such that some rule is met.

in this case, the rule is:

"Each number is 4 less than 3 times the previous number".

And we are told to start with the number 1, so the second number will be:

n₂ = 3*(1) - 4 = -1

The third number will be:

n₃ = 3*(-1) - 4 = -3 - 4 = -7

The fourth number will be:

n₄ = 3*(-7) - 4 = -21 - 4 = -25

The fifth number will be:

n₅ = 3*(-25) - 4 = -79

Then the sequence of 5 numbers for the given rule and inital number is:

{1, -1, - 7, -25, -79}

If you want to learn more about sequences:

brainly.com/question/6561461

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