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UNO [17]
3 years ago
13

A bucket contains 6 green rubber balls, 4 red rubber balls, and 8 purple rubber balls. Alex removes 3 rubber balls, without repl

acement, from the bucket. What is the probability that Alex removes a green ball, red ball, and purple ball in that order?
Mathematics
1 answer:
Vlada [557]3 years ago
8 0

in total there are 6,4,8 which equals 18 .There are 18 balls in total. but Alex removed 3 so now there are 15 balls. There 3 different colors and 15 balls. So there is a 5% out of 15 that you will get a certain color .To find the probability you need to calculate all the possible outcomes.

G=Green   R=Red    P=Purple

G,R,P

G,P,R

P,G,R

P,R,G

R,P,G,

R,G,P

There is 6 different outcomes, 15 balls and a 5% chance to get a certain color so if you want to exactly get G,R,P there is a (15 divided by 6) chance to get that order.

(I'm not good at calculating that part.)

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A store sells flower arrangements at a cost of $28 each. Which statements are true regarding the price of the arrangements? Chec
Maru [420]

Let's check each case to determine the solution to the problem.

we know that

The cost of each flower  arrangements is \$28

Statements

<u>case A)</u> If the price is marked down by 10 percent, the new price will be \$25.20

we know that

If the price is marked down by 10 percent

then

the new price will be

10\%= \frac{10}{100} =0.10  

(1-0.10)*\$28=0.90*\$28 \\= \$25.20

\$25.20=\$25.20

therefore

The statement case A) is True

<u>case B)</u> If the price is marked down by 25 percent, the new price will be \$21

we know that

If the price is marked down by 25 percent

then

the new price will be

25\%= \frac{25}{100} =0.25  

(1-0.25)*\$28=0.75*\$28 \\= \$21

\$21=\$21

therefore

The statement case B) is True

<u>case C)</u> If the price is marked down by 50 percent, the new price will be \$19

we know that

If the price is marked down by 50 percent

then

the new price will be

50\%= \frac{50}{100} =0.50  

(1-0.50)*\$28=0.50*\$28 \\= \$14

\$14 \neq \$19

therefore

The statement case C) is False

<u>case D)</u> If the price is marked down by 35 percent, the new price will be \$18.20

we know that

If the price is marked down by 35 percent

then

the new price will be

35\%= \frac{35}{100} =0.35  

(1-0.35)*\$28=0.65*\$28 \\= \$18.20

\$18.20=\$18.20

therefore

The statement case D) is True

<u>case E)</u> If the price is marked down by 40 percent, the new price will be \$29.80

we know that

If the price is marked down by 40 percent

then

the new price will be

40\%= \frac{40}{100} =0.40  

(1-0.40)*\$28=0.60*\$28 \\= \$16.80

\$16.80 \neq \$29.80

therefore

The statement case E) is False


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Contact [7]
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These would be 2 of the 4 equations, because 6 times 9 equals 54 and 9 times 6 equals 54, but are written in a different way. Thus meaning they are 2 of the 4 equations.

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These 2 would be the final to, because 54 divided by 6 is 9, and 54 divided by 9 is 6. Thus meaning they are the final 2 equations.

I hope this helps!

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