Rita = $150
Bob = $150 - $35 = $115 Bob has $115
Joe = $115 divided by 5 = $23 $23 x 4 = $92 Joe Has $92
Tim = Has $50 more then joe, $92 + $50 = $142 Tim has $142
Add like terms and put x in the middle.
-3 < -2x + x - 3x ≤ 5 - 2
-3 < - 4x ≤ 3
Sign changed when divide by negative numbers
(3/4) > x ≥ (-3/4)
Answer:
The expected value for a student to spend on lunch each day = $5.18
Step-by-step explanation:
Given the data:
Number of students______$ spent
2 students______________$10
1 student________________$8
12 students______________$6
23 students______________$5
8 students_______________$4
4 students_______________$3
Sample size, n = 50.
Let's first find the value on each amount spent with the formula:
Therefore,
For $10:
For $8:
l
For $6:
For $5:
For $4:
For $3:
To find the expected value a student spends on lunch each day, let's add all the values together.
Expected value =
$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24
= $5.18
Therefore, the expected value for a student to spend on lunch each day is $5.18
C can be -8 or 16 and the value of m is 2
If he starts paying after four years, the worth of the loans by then is b. $31,616.16
<h3>What is a Loan?</h3>
This refers to the amount collected from a lender to be repaid after a given time, usually with added interest.
Hence, we can see that:
The effective monthly interest rate is:
i = 0.053/12 = 0.0044
The effective annual interest rate is:
i = (1 + 0.0044)^12 -1 = 0.0543
The present worth of all the loans is:
P = 6125 + 6125 (1 + 0.0543)^-1 + 6125 (1 + 0.0543)^-2 + 6125(1 + 0.0543)^-3
P = $22,671.40
If he pays them prompty, then the total lifetime cost would be
P = 22671.40 (1 + 0.0543)^4 = $31,616.16
Read more about loans here:
brainly.com/question/2363571
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