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Zolol [24]
3 years ago
11

PLEASE HELP WILL GIVE BRAINLIST PLEASEEEEEEEEEE

Mathematics
2 answers:
Amiraneli [1.4K]3 years ago
5 0

Answer:

I think it would be c 160

Step-by-step explanation:

Ad libitum [116K]3 years ago
3 0

Answer:

The answer is C) 160ft2

Step-by-step explanation:

I got the answer because if you multiply the number of feet that make up that one side of the tent, you get 40. However, you need the to find out the feet of the whole tent, and there are four sides of the tent, so you'd have to multiply 40 by four to get the total amount of feet for the whole tent which comes out to 160.

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11. The news reports that today's high temperature is 16°F colder than
LenaWriter [7]

Answer:

2x3+6x2/5x3 thats the expression

Step-by-step explanation:

3 0
3 years ago
Shortern this expression pls​
pogonyaev

Answer:

c =\frac{8}{3}

Step-by-step explanation:

Given

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Required

Shorten

We have:

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}}

Rationalize

c = \sqrt{\frac{4 + \sqrt 7}{4 - \sqrt 7} * \frac{4 + \sqrt 7}{4 + \sqrt 7}} +  \sqrt{\frac{4 - \sqrt 7}{4 + \sqrt 7}*\frac{4 - \sqrt 7}{4 - \sqrt 7}}

Expand

c = \sqrt{\frac{(4 + \sqrt 7)^2}{4^2 - (\sqrt 7)^2}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{4^2 - (\sqrt 7)^2}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{16 - 7}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{16 - 7}

c = \sqrt{\frac{(4 + \sqrt 7)^2}{9}} +  \sqrt{\frac{(4 - \sqrt 7)^2}{9}

Take positive square roots

c =\frac{4 + \sqrt 7}{3} +  \frac{4 - \sqrt 7}{3}

Take LCM

c =\frac{4 + \sqrt 7 + 4 - \sqrt 7}{3}

Collect like terms

c =\frac{4  + 4+ \sqrt 7 - \sqrt 7}{3}

c =\frac{8}{3}

4 0
3 years ago
The perimeter of the square park is 240m, then the side of the square park is _______.
bagirrra123 [75]

Answer:

side of square = 60 m

Step-by-step explanation:

perimeter of square = 4 × side

so,

=》240 = 4 × side

=》240 / 4 = side

=》 60 m = each side of the square .

i hope it helped..

7 0
3 years ago
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