Step-by-step explanation:
1.(4,9) & (1,6)
m=y²-y¹/x²-x¹
m=6-9/1-4
m=-3/-3
m= 1
2.(5,3) & (5,-9)
m=y²-y¹/x²-x¹
m=(-9)-3/5-5
m=-12/0
3.(2,1) & (8,9)
m=y²-y¹/x²-x¹
m=9-1/8-2
m=8/6
m= 4/3
4.(14,-8) & (7,-6)
m=y²-y¹/x²-x¹
m=(-6)-(-8)/7-14
m=2/-7
m= -2/7
5.(4,-3) & (8,-3)
m=y²-y¹/x²-x¹
m=(-3)-(-3)/8-4
m=0/4
m=0
6.(-11,1) & (-2,6)
m=y²-y¹/x²-x¹
m=6-1/(-2)-(-11)
m=5/9
Answer:
The width of rectangle is 1 unit.
Step-by-step explanation:
Given:
The area of rectangle is 6 units and its width is 5 units less than the length.
So, to find the width of rectangle.
Let the length be
and the width be
.
Now, to find the width we put the formula of area of rectangle:
Area = length × width






<em>On solving equation we get:</em>

Therefore, we take the value x=6 as it is positive value:


So, the width of rectangle:
Width = 
= 
= 
Therefore, the width of rectangle is 1 unit.
Answer:
1,436.03
Step-by-step explanation:
V=4/3*pi*r^3
V=4/3*3.14*7^3
V=1,436.03