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likoan [24]
2 years ago
7

School is going to start soon for me, and if it is for you, have a good school day and don't fall asleep or you'll get called on

randomly or you'll be singing 34+35 and you'll be unmuted.
Mathematics
1 answer:
inn [45]2 years ago
7 0

Dear Gentleman Scholar —

Recently, I nearly reduced a woman to tears when she gently proffered her hand to me at a work conference and I vigorously squeezed it and yanked her around like the Incredible Hulk shaking hands with Raggedy Ann. There was much metacarpal cracking and muted whimpering. Having (I thought) learned my lesson, later at the same event when another women extended her hand, I very gently held hers and then released. There were no injuries this time, but she glared at me as if I had just handed her a dead fish. How does a gentleman shake hands with a lady? Am I supposed to shake it, caress it, kiss it, just hold it for a moment? What gives?

Yours,

Finishing School Dropout

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in the equation y equals 8X y is the dependent variable and X is the independent variable what happens to the dependent variable
goblinko [34]
As the independant variable increases, the dependant variable increases at a constant rate creating a linear relationship.
4 0
3 years ago
For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.
Anni [7]

Answer:

The reduced row-echelon form of the linear system is \left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

  1. Interchange two rows
  2. Multiply one row by a nonzero number
  3. Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]

You need to follow these steps:

  • Divide row 1 by 2 \left(R_1=\frac{R_1}{2}\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]

  • Subtract row 1 from row 2 \left(R_2=R_2-R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]

  • Subtract row 1 multiplied by 5 from row 3 \left(R_3=R_3-\left(5\right)R_1\right)

\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 1 \left(R_1=R_1-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]

  • Subtract row 2 multiplied by 3 from row 3 \left(R_3=R_3-\left(3\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]

  • Multiply row 2 by 2 \left(R_2=\left(2\right)R_2\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]

  • Divide row 3 by −19 \left(R_3=\frac{R_3}{-19}\right)

\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]

  • Subtract row 3 multiplied by 16 from row 1 \left(R_1=R_1-\left(16\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]

  • Add row 3 multiplied by 6 to row 2 \left(R_2=R_2+\left(6\right)R_3\right)

\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]

8 0
3 years ago
What is the answer to these two
Serggg [28]

Answer:

1.) m<6 and m<8=142, m<9=38

2.) m<7 and m<9=66, m<8=114

note: brainliest would be appreciated.

Step-by-step explanation:

8 0
2 years ago
a town has a population of 14000 and grows at 4.5% each year. to the nearest tenth of a year how long will it be until the popul
denis-greek [22]

Answer:

about 6.6 years

Step-by-step explanation:

41,500=14,000*.45*x

41,500=6,300*x

41,000/6,300=x

6.5873=x

6.6=x

6 0
2 years ago
I need help with this
adoni [48]
Answer is D
Mark me the brainliest
6 0
2 years ago
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