1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tasya [4]
3 years ago
15

Ashley has some pennies and some nickels. She has at most 22 coins worth a minimum of $0.78 combined. If Ashley has 4 pennies, d

etermine the minimum number of nickels that she could have. If there are no possible solutions, submit an empty answer.
Mathematics
2 answers:
Shalnov [3]3 years ago
8 0

Answer:

The minimum number of nickels that she could have is 15

Step-by-step explanation:

Let x represent the number of nickels Ashley has. If she has 4 pennies and has at most 22 coins, then

→ x + 4 <= 22

→ x <= 18    (1)

Her coins worth a minimum $0.78. Also, it is known that 1 dollar is equal to 100 cents and 1 nickel is equal to 5 cents.

→ (x * 5) + 4 >= 78

→ 5x >= 74

→ x >= 14.8  (2)

If we combine the equation 1 and 2:

14.8 <= x <= 18

The minimum value of x is 15

Licemer1 [7]3 years ago
4 0

Answer:

18 nickels

Step-by-step explanation:

4 pennies = $0.04. 22 coins minus the 4 pennies = 18. So, 18 nickels is equal to $0.90. Because she has at most 22 coins and they're worth at least $0.78 then $0.94 would make since.

You might be interested in
Find the derivative of the function f(x)2x^4+x^3-x^2+4
eduard

Answer:

Step-by-step explanation:

can i pls have brainliest??

3 0
3 years ago
Find the area of the following<br> kite:<br> A = [?] m²<br> 40 m<br> 16 m<br> 16 m<br> 6 m
Rama09 [41]

Answer:

Area_{kite}=736m^2

Step-by-step explanation:

There are a few methods to find the area of this figure:

1. kite area formula

2. 2 triangles (one top, one bottom)

3. 2 triangles (one left, one right)

4. 4 separate right triangles.

<h3><u>Option 1:  The kite area formula</u></h3>

Recall the formula for area of a kite:  Area_{kite}=\frac{1}{2} d_{1}d_{2} where d1 and d2 are the lengths of the diagonals of the kite ("diagonals" are segments that connect non-adjacent vertices -- in a quadrilateral, vertices that are across from each other).

If you've forgotten why that is the formula for the area of a kite, observe the attached diagram: note that the kite (shaded in) is half of the area of the rectangle that surrounds the kite (visualize the 4 smaller rectangles, and observe that the shaded portion is half of each, and thus the area of the kite is half the area of the large rectangle).

The area of a rectangle is Area_{rectangle}=bh, sometimes written as Area_{rectangle}=bh, where w is the width, and h is the height of the rectangle.

In the diagram, notice that the width and height are each just the diagonals of the kite.  So, the <u>Area of the kite</u> is <u>half of the area of that surrounding rectangle</u> ... the rectangle with sides the lengths of the kite's diagonals.Hence, Area_{kite}=\frac{1}{2} d_{1}d_{2}

For our situation, each of the diagonals is already broken up into two parts from the intersection of the diagonals.  To find the full length of the diagonal, add each part together:

For the horizontal diagonal (which I'll call d1): d_{1}=40m+6m=46m

For the vertical diagonal (which I'll call d2): d_{2}=16m+16m=32m

Substituting back into the formula for the area of a kite:

Area_{kite}=\frac{1}{2} d_{1}d_{2}\\Area_{kite}=\frac{1}{2} (46m)(32m)\\Area_{kite}=736m^2

<h3><u /></h3><h3><u>Option 2:  The sum of the parts (version 1)</u></h3>

If one doesn't remember the formula for the area of a kite, and can't remember how to build it, the given shape could be visualized as 2 separate triangles, the given shape could be visualized as 2 separate triangles (one on top; one on bottom).

Visualizing it in this way produces two congruent triangles.  Since the upper and lower triangles are congruent, they have the same area, and thus the area of the kite is double the area of the upper triangle.

Recall the formula for area of a triangle:  Area_{triangle}=\frac{1}{2} bh where b is the base of a triangle, and h is the height of the triangle <em>(length of a perpendicular line segment between a point on the line containing the base, and the non-colinear vertex)</em>.  Since all kites have diagonals that are perpendicular to each other (as already indicated in the diagram), the height is already given (16m).

The base of the upper triangle, is the sum of the two segments that compose it:  b=40m+6m=46m

<u>Finding the Area of the upper triangle</u>Area_{\text{upper }triangle}=\frac{1}{2} (46m)(16m) = 368m^2

<u>Finding the Area of the kite</u>

Area_{kite}=2*(368m^2)

Area_{kite}=736m^2

<h3><u>Option 3:  The sum of the parts (version 2)</u></h3>

The given shape could be visualized as 2 separate triangles (one on the left; one on the right).  Each triangle has its own area, and the sum of both triangle areas is the area of the kite.

<em>Note:  In this visualization, the two triangles are not congruent, so it is not possible to  double one of their areas to find the area of the kite.</em>

The base of the left triangle is the vertical line segment the is the vertical diagonal of the kite.  We'll need to add together the two segments that compose it:  b=16m+16m=32m.  This is also the base of the triangle on the right.

<u>Finding the Area of left and right triangles</u>

Area_{\text{left }triangle}=\frac{1}{2} (32m)(40m) = 640m^2

The base of the right triangle is the same length as the left triangle: Area_{\text{right }triangle}=\frac{1}{2} (32m)(6m) = 96m^2

<u>Finding the Area of the kite</u>

Area_{kite}=(640m^2)+(96m^2)

Area_{kite}=736m^2

<h3><u>Option 4:  The sum of the parts (version 3)</u></h3>

If you don't happen to see those composite triangles from option 2 or 3 when you're working this out on a particular problem, the given shape could be visualized as 4 separate right triangles, and we're still given enough information in this problem to solve it this way.

<u>Calculating the area of the 4 right triangles</u>

Area_{\text{upper left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2

Area_{\text{upper right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2

Area_{\text{lower left }triangle}=\frac{1}{2} (40m)(16m) = 320m^2

Area_{\text{lower right }triangle}=\frac{1}{2} (6m)(16m) = 48m^2

<u>Calculating the area of the kite</u>

Area_{kite}=(320m^2)+(48m^2)+(320m^2)+(48m^2)

Area_{kite}=736m^2

8 0
2 years ago
0.5 is 5 % of what number ?
Mrrafil [7]
It would be .10 bc they are both decimals
5 0
4 years ago
Read 2 more answers
Multiply. - 4.3 x - 3.2 = _____.
GarryVolchara [31]
The answer is
13.76 because when u multiply negative times negative it gives u a positive
4 0
3 years ago
Read 2 more answers
2 x -1^2 + 1<br><br> please show me how to get to the answer of 1
OLga [1]

Answer:

-1

Step-by-step explanation:

2 × (-1²) + 1 = 2 × (-1) + 1 = -2 + 1 = -1

7 0
2 years ago
Read 2 more answers
Other questions:
  • What dose p equal p+7-5=-10-3p
    6·2 answers
  • Help plz <br> Help<br> Help<br> Help
    10·2 answers
  • Write 10/25 (Fraction) in lowest terms
    15·2 answers
  • The system of equations has how many solutions? y=-3/2x+5 and y=-3/2x-3
    10·1 answer
  • A line that includes the points (9,j) and (10,4) has a slope of 1. What is the value of j?
    7·2 answers
  • Twenty-four percent of the 25 swim team members are new on the team . how many members are new?
    7·2 answers
  • If y=a sin 3x+ b cos 3x and <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bd%5E%7B2%7D%20y%20%7D%7Bdx%5E%7B2%7D%20%7D" id="TexFormu
    9·1 answer
  • The formula for the area of a rhombus is A= 1/2d1d2, where d1 and d2 are the length of the diagonals
    5·1 answer
  • How much cost Rs 1136 when it is 10% discount and 13% vat is added then find out the discount and Vat amount
    7·1 answer
  • According to the given information, segment uv is parallel to segment wz, while angles squ and vqt are vertical angles. angle vq
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!