The ΔABR ≅ ΔACR are congruent by SAS theorem
Option D is the correct answer.
The missing diagram is attched with the answer.
<h3>What is a Triangle ?</h3>
A triangle is a polygon with three sides , three vertices and three angles.
SAS will be used to prove the congruence of ΔABR ≅ ΔACR
In both the triangle we have a common side , AR
AB = AC (given)
∠ B A R = ∠R A C ( given equal)
So as the two side and the included angle is equal
Therefore the ΔABR ≅ ΔACR are congruent by SAS theorem
Option D is the correct answer.
To know more about Triangle
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Answer:
0.30
Step-by-step explanation:
$6 Total
20 markers
6/20=0.30
0.3 per maker.
Cost of 1 marker is $0.30
Answer:
y=90 degree
Step-by-step explanation:
bcz this triangle is drawn in the semi-circle and the greatest angle of triangle in a semi-circle is always right angle.
Answer:
y = 3/5x + 62/5
Step-by-step explanation:
Equation of a line with two points is
m = y - y_1 / x - x _1
m = y_2 - y_1 / x_2 - x _1
Equating both
y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1
Using what we are provided with
(-4 , 10)(16 , -2)
x_1 = -4
y_1 = 40
x_2 = 16
y_2 = -2
Imputing the values
10 - (-2) / 16 - (-4) = y - 10 / x - (-4)
10 + 2 /16 + 4 = y - 10 / x + 4
12 / 20 = y - 10 / x + 4
Lets cross multiply
12 ( x + 4) = 20(y - 10)
Open the brackets
12x + 48 = 20y - 200
12x + 48 + 200 = 20y
12x + 248 = 20y
Following this equation of line
y = mx + C
20y = 12x + 248
Let's divide through by 20 to get y.
20y / 20 = 12x + 248 / 20
y = 12x + 248 / 20
We can separate it by
y = 12x / 20 + 248 / 20
y = 3/5x + 62/5
Therefore, the equation of the line is
y = 3/5x + 62/5
