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Likurg_2 [28]
3 years ago
15

Find all values of a such that (a-3)/sqrta=-sqrta

Mathematics
1 answer:
Mariana [72]3 years ago
3 0

Answer:

From the Pythagorean theorem...

 

[ distance between (a, 7)  and  (2, 1) ]2   =   [a - 2]2  +  [7 - 1]2

 

And they tell us that the distance equals  3√5  , so

 

[  3√5 ]2   =   [a - 2]2  +  [7 - 1]2

 

45   =   [a - 2]2  +  36

 

9   =   [a - 2]2

 

±√9  =   a - 2

 

± 3   =   a - 2

 

± 3  +  2   =   a

 

a  =  3 + 2  =  5          or          a = -3 + 2  =  -1

 

and

 

5  +  -1   =   4

Step-by-step explanation:

hope dis helps

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Kim caught a fish that was 9/10 of a meter long. Doug caught a fish that was 2/3 as long as kim's fish
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Kim caught a fish that was 9/10 of a meter long. Doug caught a fish that was 2/3 as long as Kim's fish. So, Doug caught a fish that was 3/5 meters long.

<h3>What is the fundamental principle of multiplication?</h3>

If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways

Kim caught a fish that was 9/10 of a meter long. Doug caught a fish that was 2/3 as long as Kim's fish.

Kim caught a fish of length = 9/10 m

Doug caught a fish of length = 2/3 as long as Kim's fish.

                                                 = 2/3 x 9/10

                                                 = 18 / 30

                                                 = 3/5

Thus, Doug caught a fish that was 3/5 meters long.

Learn more about multiplications;

brainly.com/question/14059007

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