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Anna [14]
3 years ago
15

B=3 V/h I’m supposed to solve the question for V.

Mathematics
1 answer:
FromTheMoon [43]3 years ago
6 0
Answer:
V=Bh/3

Explanation:
B=3V/h
1) Multiply h on both sides.
Bh=3v
2) Divide both sides by 3
Bh/3=V
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I really need help please
konstantin123 [22]

Answer:

7 muffins

Step-by-step explanation:

First, you must figure out how many times 9 can go into 88. That gives you 9.8. This tells you that 9 boxes will be filled completely. You then multiply 9 by 9 to figure out how many muffins that will be (81). Lastly, you subtract those (81) from the total muffins to find out how many muffins are left that will be in the small box.

8 0
3 years ago
Simplify a^2-3a2 a^3-8a^2+12a to lowest terms
inn [45]

Answer:

\frac{a-3}{(a-2)(a-6)}

Step-by-step explanation:

a^{2}-3a has the common multiple of a. If you factor it out, you get a(a-3).

a^3-8a^2+12a also has a common multiple of a. Once factored, you get a(a^2-8a+12). This equation can be further factored to get (a-2)(a-6).

Put these two expressions over one another and you get  \frac{a-3}{(a-2)(a-6)}.

6 0
2 years ago
Kelly can draw 15 shapes in 2 minutes how long does it take kelly to draw 120 shapes in the same rate
Serga [27]

Answer:

16

Step-by-step explanation:

15/120

2/x     (cross multiplication

6 0
3 years ago
Read 2 more answers
There are five seniors in a class. For each situation, write how the binomial formula is used to calculate the probability.
ololo11 [35]
A) The answer is 5.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
<span>I choose one senior: r = 1
</span>
nCr = n! / (r! (n - r)!)
5C1 = 5! / (1! (5 - 1)!)
       = (5 * 4 * 3 * 2 * 1) / (1 * 4!)
       = 120 / (4 * 3 * 2 * 1)
       = 120 / 24
       = 5

b) The answer is 10.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose two seniors: r = 2

nCr = n! / (r! (n - r)!)
5C2 = 5! / (2! (5 - 2)!)
       = (5 * 4 * 3 * 2 * 1) / ((2 * 1) * 3!)
       = 120 / (2 * (3 * 2 * 1))
       = 120 / (2 * 6)
       = 120 / 12
       = 10


c) The answer is 10.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose three seniors: r = 3

nCr = n! / (r! (n - r)!)
5C3 = 5! / (3! (5 - 3)!)
       = (5 * 4 * 3 * 2 * 1) / ((3 * 2 * 1) * 2!)
       = 120 / (6 * (2 * 1))
       = 120 / (6 * 2)
       = 120 / 12
       = 10


d) The answer is 5.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose four seniors: r = 4

nCr = n! / (r! (n - r)!)
5C4 = 5! / (4! (5 - 4)!)
       = (5 * 4 * 3 * 2 * 1) / ((4 * 3 * 2 * 1) * 1!)
       = 120 / (24 * 1)
       = 120 / 24
       = 5


e) The answer is 1.

nCr = n! / (r! (n - r)!)
n - number of things to be chosen from
r - number of chosen things

There are five seniors in a class: n = 5
I choose five seniors: r = 5

nCr = n! / (r! (n - r)!)
5C5 = 5! / (5! (5 - 5)!)
       = (5 * 4 * 3 * 2 * 1) / ((5 * 4 * 3 * 2 * 1) * 1!)
       = 120 / (120 * 1)
       = 120 / 120
       = 1
8 0
3 years ago
Which process will transform Figure A onto Figure B ?
Karolina [17]

Answer:

1st option

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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