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snow_lady [41]
3 years ago
6

What steps should be taken to complete the conversion?

Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer:

The third option should be correct please correct me if im wrong

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Is 2:3 and 10:15 equivalent
olga_2 [115]

Answer:

Yes. It is.

Hope this helped!

5 0
4 years ago
Read 2 more answers
Write the equation of a line perpendicular to y = -5x + 1 that goes through (10. 4).
alexandr1967 [171]

Answer:

y = 1/5x + 2

Step-by-step explanation:

y = 1/5x + b

4 = 1/5(10) + b

4 = 2 + b

2 = b

4 0
3 years ago
GIVING BRAINLIEST FOR BEST ANSWER!<br> Write a story that could represent this math problem.
xenn [34]

Answer:

Step-by-step explanation:

The third pig is only 2/3 of the way done with his strawberry house, the fourth pig builds a house out of sticks he’s only 2/3 of the way there, the last pig builds a house out of bricks he’s only 2/3 of the way there.

3 0
2 years ago
Pls helppppppppppplppppppppp
kenny6666 [7]

Answer:

Step-by-step explanation:

3 0
3 years ago
A procurement specialist has purchased 25 resistors from vendor 1 and 30 resistors from vendor 2. Let
Ulleksa [173]

Answer:

Normal Distribution

Standard error = 0.473

Step-by-step explanation:

We are given the following information:

A procurement specialist has purchased 25 resistors from vendor 1  are assumed to be normally distributed with mean 100 ohms and standard deviation 1.5 ohms.

x_{1,1}, x_{1,2}, ... , x_{1,25}\\\mu_{1} = 100\\\sigma_1 = 1.5

A procurement specialist has purchased 30 resistors from vendor 2 are assumed to be normally distributed with mean 105 ohms and standard deviation 2.0 ohms.

x_{2,1}, x_{2,2}, ... , x_{2,30}\\\mu_{2} = 105\\\sigma_1 = 2.0

The difference of two independent normally distributed random variables is normal, with its mean being equal to the difference of the two means, and its variance being the sum of the two variances.

Thus, the sampling distribution of X_1-X_2 is a normal distribution.

Mean =

100 - 105 = -5

Standard error =

\sqrt{\displaystyle\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}}\\\\=\sqrt{\displaystyle\frac{(1.5)^2}{25} + \frac{(2)^2}{30}}\\\\= 0.473

8 0
3 years ago
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