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1 year ago

Which of the following is located over the center of the base of a regular pyramid

Mathematics

1 answer:

kenny6666 [7]1 year ago

5 0

Vertex is located over the center of the base of a regular pyramid.

<h3>What is Vertex Angle?</h3>

Vertex angle is defined as the angle formed by two lines or rays that intersect at a point. These two rays make the sides of the angle.

Here, Vertex is the point which is located over the center of the base of a regular pyramid.

Learn more about Vertex angle from:

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What is the solution to the system of equations y23x3 x 2

bija089 [108]

The Solution for the given system of equations is (-2) and $(\frac{5}{3})$ .

The given are linear equations as follow:
y = $\frac{2}{3}x$ + 3 .. ... ...(1)
and x = -2. .. .... ...(2)

We already know the first part of the solution (x) which is -2. We can find the other part (y) by putting the value of equation (2) in equation (1).

By putting the values of x in equation (1), we get

y = $(\frac{2}{3})(-2)$ + 3
y = $\frac{-4}{3}$ + 3

Taking the L. C. M of denominators which will be '3', we get:

y = $\frac{-4 + 9}{3}$

y = $\frac{5}{3}$

So the second part (y) of the solution of the given equation is $\frac{5}{3}$ .

Hence, the overall solution to the given system of equation is $(-2, \frac{5}{3})$ .

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8 0

1 year ago

a circular garden has a diameter of 12 feet. what is the best approximation for the circumference of the garden? use 3.14 to app

Nuetrik [128]

Answer:

37.68

Step-by-step explanation:

C(circumference)= 2pi r

If the diameter is 12, the r adius is 6

plug into equation

2(pi)(6)

=12pi

=37.68

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2 years ago

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kkurt [141]

Answer:

answer is A. cosine

Step-by-step explanation:

8 0

2 years ago

1/(cot^2 (x)) - 1/(cos^2 (x))

Airida [17]

Step-by-step explanation:

1 is your answer its law of trig identises

5 0

2 years ago

Read 2 more answers

Consider 8x2 - 48x = -104.

ki77a [65]

Answer:

$3+ 2\mathbf{i}$

$3- 2\mathbf{i}$

Step-by-step explanation:

<u>Quadratic Equation Solving</u>

We have the equation:

$8x^2-48x=-104$

Divide by 8:

$x^2-6x=-13$

Now complete the squares so the left side is a perfect square of a binomial:

$x^2-6x+9=-13+9=-4$

Factoring the perfect square:

$(x-3)^2=-4$

Taking the square root:

$x-3=\sqrt{-4}$

The square root of a negative number is an imaginary number:

$x-3=\pm 2\mathbf{i}$

Solving for x:

$x=3\pm 2\mathbf{i}$

The solutions are:

$3+ 2\mathbf{i}$

$3- 2\mathbf{i}$

7 0

2 years ago