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SVEN [57.7K]
3 years ago
12

It costs $0.50 to download an individual song and $4 to download an album jada has $15 to spend downloading music how many album

s can jada download is she downloads 6 individual songs
Mathematics
2 answers:
GREYUIT [131]3 years ago
6 0

Answer:

^^3

Step-by-step explanation: If she has $15 and she has already downloaded 6 individual songs, and they cost .50, that leaves her with $12 to spend, which is 3 albums. Hope this helps!

natali 33 [55]3 years ago
4 0

Answer:

3 albums

Step-by-step explanation:

6 x .5 = $3

15-3=12

12÷4=3

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<img src="https://tex.z-dn.net/?f=cos%20%5B%20arctan%28%5Cfrac%7B12%7D%7B5%7D%29%20-%20arcsin%20%28%5Cfrac%7B-3%7D%7B5%7D%29%5D"
qwelly [4]

Answer: -16/65

Step-by-step explanation:

Drawing the right triangle (as attached) gives us that \arctan \left(\frac{12}{5} \right)=\arcsin \left(\frac{12}{13} \right)

Also, -\arcsin \left(-\frac{3}{5} \right)=\arcsin \left(\frac{3}{5} \right)

This means our original expression is equal to:

\cos \left[\arcsin \left(\frac{12}{13} \right)+\arcsin \left(\frac{3}{5} \right) \right]

Using the cosine addition formula, which states \cos(a+b)=\cos a \cos b-\sin a \sin b, we get this itself is equal to:

\cos \left(\arcsin \left(\frac{12}{13} \right) \right)\cos \left(\arcsin \left(\frac{3}{5} \right)\right)-\sin \left(\arcsin \left(\frac{12}{13} \right) \right)\sin \left(\arcsin \left(\frac{3}{5} \right)\right)

Since \sin^{2} \theta+\cos^{2} \theta=1, we know that:

\sin^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)+\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\\frac{144}{169} +\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=1\\\\cos^{2} \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{25}{169}\\\\cos \left(\arcsin \left(\frac{12}{13} \right)\right)=\frac{5}{13}

Similarly, cos(arcsin(3/5))=4/5.

This means the given expression is equal to:

\left(\frac{5}{13} \right) \left(\frac{4}{5} \right)-\left(\frac{12}{13} \right) \left(\frac{3}{5} \right)\\\\\frac{20}{65}-\frac{36}{65}=\boxed{-\frac{16}{65}}

3 0
2 years ago
Find the lcm for 8 and 56
ale4655 [162]

8 · 7 = 56, therefore LCM(8, 56) = 56.

8 0
4 years ago
Find the exact values of sin(u/2) cos(u/2) and tan(u/2) given sin u=24/25 and pie/2 &lt; u &lt; pie
vlada-n [284]

Recall the double/half angle formulas:

\cos^2\dfrac x2=\dfrac{1+\cos x}2

\sin^2\dfrac x2=\dfrac{1-\cos x}2

We're given \sin u=\frac{24}{25}, and since u is between π/2 and π, we expect \cos u to be negative. So from the Pythagorean identity, we find

\sin^2u+\cos^2u=1\implies\cos u=-\sqrt{1-\sin^2u}=-\dfrac7{25}

Also, we know \frac u2 will fall between π/4 and π/2, so both \sin\frac u2 and \cos\frac u2 will be positive. Then we find

\cos\dfrac u2=\sqrt{\dfrac{1+\cos u}2}=\dfrac35

\sin\dfrac u2=\sqrt{\dfrac{1-\cos u}2}=\dfrac45

and it follows that

\tan\dfrac u2=\dfrac{\sin\frac u2}{\cos\frac u2}=\dfrac43

8 0
4 years ago
What is the value of a for the exponential function in the graph represented in the form of f(x) = a(bx)? −4 −3 3 4
Westkost [7]

Answer:

It's c

Step-by-step explanation:

9 0
4 years ago
Read 2 more answers
Help needed asap graph posted below
Aloiza [94]
Answer: D) (x+1)(x + 2)(x-3)

This is because the roots are x = -1, x = -2 and x = 3
Simply get all the numbers to each side to have 0 on the right side

x = -1 turns into x+1 = 0
x = -2 turns into x+2 = 0
x = 3 turns into x-3 = 0

The three factors are (x+1), (x+2) and (x-3)
Which leads to (x+1)(x+2)(x-3)

6 0
3 years ago
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