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Genrish500 [490]
3 years ago
8

Descubre el número que falta​

Mathematics
1 answer:
Vladimir79 [104]3 years ago
5 0
I only speak English
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Answer:

x = 3.69 feet

11.69 x 13.69 feet

Step-by-step explanation:

new area = (8 x 10) x 2 = 160

(8 + x)(10 + x) = 160

80 + 8x + 10x + x² = 160

combine like terms:

x² + 18x - 80 = 0

factor:

(x - 3.69)(x + 21.69) = 0

x = 3.69

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3. A serving of chocolates cookies contains 1600 calories. One hundred thirty-five calories comes from fat. What percent of the
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11.85%

Step-by-step explanation:

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4 0
3 years ago
A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
saul85 [17]

Answer:

The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

He takes a simple random sample of 122 people living in Gastown and finds that 25 have an annual income that is below the poverty line. This means that n = 122 and \pi = \frac{25}{122} = 0.205

We have \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.205 - 1.96\sqrt{\frac{0.205*0.795}{122}} = 0.133

The upper limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.205 + 1.96\sqrt{\frac{0.205*0.795}{122}} = 0.133 = 0.2766

The 95% confidence interval for the true proportion of Gastown residents living below the poverty line is (0.133, 0.2766).

7 0
3 years ago
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