Possible Answer:
Millimeter.
Step-by-step explanation:
Judging by the item in the question, a straw, millimeter is probably the correct measurement of the width of it.
The surface area of cone B is 10 km², and Cone B is the image of cone A after dilation by a scale factor of 1/2
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more numbers and variables.
Cone B is the image of cone A after dilation by a scale factor of 1/2, hence:
Surface area of cone B = 40 km² * (1/2)² = 10 km²
The surface area of cone B is 10 km², and Cone B is the image of cone A after dilation by a scale factor of 1/2
Find out more on equation at: brainly.com/question/2972832
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Please ask the question in English, if you are not able to, I believe you are in the wrong language section and suggest you try something else before you get your question taken down.
Answer:
Using either method, we obtain: 
Step-by-step explanation:
a) By evaluating the integral:
![\frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdt%7D%20%5Cint%5Climits%5Et_0%20%7B%5Csqrt%5B8%5D%7Bu%5E3%7D%20%7D%20%5C%2C%20du)
The integral itself can be evaluated by writing the root and exponent of the variable u as: ![\sqrt[8]{u^3} =u^{\frac{3}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B8%5D%7Bu%5E3%7D%20%3Du%5E%7B%5Cfrac%7B3%7D%7B8%7D)
Then, an antiderivative of this is: 
which evaluated between the limits of integration gives:

and now the derivative of this expression with respect to "t" is:

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:
"If f is continuous on [a,b] then

is continuous on [a,b], differentiable on (a,b) and 
Since this this function
is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

MNOP is similar to QRST with ratio of 5:4<span>. That means the MP:QT ratio would also be 5:4
The length of QT would be
</span>MP/QT = 5/4<span>
85mm/QT=5/4
85mm*4= 5*QT
5QT= 340
QT=68mm</span>