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Pavel [41]
4 years ago
11

A gas can is filled at the rate of 320 cubic inches per minute. The can is 10 inches long, 8 inches wide, and 12 inches high. Ho

w many minutes will it take to fill the can
Mathematics
2 answers:
Sav [38]4 years ago
7 0
The volume is 960 cu in. 3 minutes
elena-14-01-66 [18.8K]4 years ago
6 0

Solution:

The gas can is filled at the rate of 320 cubic inches per minute.

The can is 10 inches long, 8 inches wide, and 12 inches high.

So volume of the can=10 in*8 in *12 in

\text{Volume of can }=960  \ in^3\\

Time required to fill the can=\frac{960}{320}=3  \ minutes\\

Hence Time required to fill the can =3 minutes.

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The opening of the drinking straw was about 6 ? wide.​
dimulka [17.4K]

Possible Answer:

Millimeter.

Step-by-step explanation:

Judging by the item in the question, a straw, millimeter is probably the correct measurement of the width of it.

8 0
3 years ago
Cone B is the image of cone A after dilation by a scale factor of \frac{1}{2}
Bogdan [553]

The surface area of cone B is 10 km², and Cone B is the image of cone A after dilation by a scale factor of 1/2

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Cone B is the image of cone A after dilation by a scale factor of 1/2, hence:

Surface area of cone B = 40 km² * (1/2)² = 10 km²

The surface area of cone B is 10 km², and Cone B is the image of cone A after dilation by a scale factor of 1/2

Find out more on equation at: brainly.com/question/2972832

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4 0
2 years ago
Fie ABCDA'B'C'D' o piramida dreapta cu baza un patrat ABCD. Lungimea laturilor AB si AA' sunt direct proportionale cu numerele 3
ASHA 777 [7]
Please ask the question in English, if you are not able to, I believe you are in the wrong language section and suggest you try something else before you get your question taken down. 
8 0
3 years ago
Find the derivative.
Aleksandr [31]

Answer:

Using either method, we obtain:  t^\frac{3}{8}

Step-by-step explanation:

a) By evaluating the integral:

 \frac{d}{dt} \int\limits^t_0 {\sqrt[8]{u^3} } \, du

The integral itself can be evaluated by writing the root and exponent of the variable u as:   \sqrt[8]{u^3} =u^{\frac{3}{8}

Then, an antiderivative of this is: \frac{8}{11} u^\frac{3+8}{8} =\frac{8}{11} u^\frac{11}{8}

which evaluated between the limits of integration gives:

\frac{8}{11} t^\frac{11}{8}-\frac{8}{11} 0^\frac{11}{8}=\frac{8}{11} t^\frac{11}{8}

and now the derivative of this expression with respect to "t" is:

\frac{d}{dt} (\frac{8}{11} t^\frac{11}{8})=\frac{8}{11}\,*\,\frac{11}{8}\,t^\frac{3}{8}=t^\frac{3}{8}

b) by differentiating the integral directly: We use Part 1 of the Fundamental Theorem of Calculus which states:

"If f is continuous on [a,b] then

g(x)=\int\limits^x_a {f(t)} \, dt

is continuous on [a,b], differentiable on (a,b) and  g'(x)=f(x)

Since this this function u^{\frac{3}{8} is continuous starting at zero, and differentiable on values larger than zero, then we can apply the theorem. That means:

\frac{d}{dt} \int\limits^t_0 {u^\frac{3}{8} } } \, du=t^\frac{3}{8}

5 0
3 years ago
MNOP is similar to QRST with a scale factor of 5 : 4. MP = 85mm. What is the value of QT?
chubhunter [2.5K]
MNOP is similar to QRST with ratio of 5:4<span>. That means the MP:QT ratio would also be 5:4

The length of QT would be
</span>MP/QT = 5/4<span>
85mm/QT=5/4
85mm*4= 5*QT
5QT= 340
QT=68mm</span>
8 0
4 years ago
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