Let L and S represent the weights of large and small boxes, respectively. The problem statement gives rise to two equations:
.. 7L +9S = 273
.. 5L +3S = 141
You can solve these equations various ways. Using "elimination", we can multiply the second equation by 3 and subtract the first equation.
.. 3(5L +3S) -(7L +9S) = 3(141) -(273)
.. 8L = 150
.. L = 150/8 = 18.75
Then we can substitute into either equation to find S. Let's use the second one.
.. 5*18.75 +3S = 141
.. S = (141 -93.75)/3 = 15.75
A large box weighs 18.75 kg; a small box weighs 15.75 kg.
Answer:
Yes..You are
Step-by-step explanation:
|Wow! Nice Job! Even though Absolute value is EXTREMELy EASY you probably aced the test!
So the question ask to find the displacement vector and the distance from the submarine to the boat. Base on my calculation the displacement value of the given data you give is <(5-3),(1-4)(-5-0)>. I hope you are satisfied with my answer and feel free to ask for more
Cos 210° = cos ( 180° + 30° ) - cos 30° = - √3/2
