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Elodia [21]
4 years ago
9

Simplify the following expression: (−3)(−2)( −2)

Mathematics
1 answer:
Art [367]4 years ago
8 0
-3*-2*-2=6*-2=-12 because negative multiplied by negative is positive
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Write an equation for the line passing through the given pair of points. give the final answer in standard form (-4,-2) and (3,-
Andrew [12]

Answer:

y = -2/7x - 22/7

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra I</u>

Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Slope-Intercept Form: y = mx + b

  • m - slope
  • b - y-intercept

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-4, -2)

Point (3, -4)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{-4+2}{3+4}
  2. Add:                              m=\frac{-2}{7}

<u>Step 3: Find y-intercept </u><em><u>b</u></em>

  1. Define:                    y = -2/7x + b
  2. Substitute:              -4 = -2/7(3) + b
  3. Multiply:                  -4 = -6/7 + b
  4. Isolate <em>b</em>:                 -22/7 = b
  5. Rewrite:                   b = -22/7

<u>Step 4: Write linear equation</u>

y = -2/7x - 22/7

7 0
3 years ago
What are the possible values of x in 2x^2-8=10
Dimas [21]

Answer:

3, -3

Step-by-step explanation:

4 0
3 years ago
You have determined that the equations x+1=y​ecks plus one is equal to why and −3x+5=y​negative three ecks plus five is equal to
Anna [14]

Answer:

b

Step-by-step explanation:

2022 on edge I just did it

5 0
2 years ago
Keisha says that all functions are relations but not all relations are functions. kevin says that all relations are functions bu
vladimir1956 [14]

Keisha is correct, because as per the definition <u>A function is a special relationship where each input has a single output</u>.

A function is a special relation. In other words, a relation if and only if it has a specific characteristic where each input has a single output, then it is called a Function.

All functions are relations but not all relations are functions.


3 0
3 years ago
A catering service offers 5 appetizers,4 main courses, and 8 desserts. A customer is to select 4 appetizers,2 main courses,and 3
Alisiya [41]

Answer:

468 ways

Step-by-step explanation:

Given: A catering service offers 5 appetizers, 4 main courses, and 8 desserts

To find: number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts.

Solution:

A permutation is an arrangement of elements such that order of elements matters and repetition is not allowed.

Number of appetizers = 5

Number of main courses = 4

Number of desserts = 8

Number of ways of choosing k terms from n terms = nPk=\frac{n!}{(n-k)!}

Number of ways a customer is to select 4 appetizers, 2 main courses,and 3 desserts =  5P4+4P2+8P3

=\frac{5!}{(5-4)!}+\frac{4!}{(4-2)!}+\frac{81}{(8-3)!}\\=5!+\frac{4!}{2!}+\frac{8!}{5!}\\=5!+(4\times 3)+(8\times 7\times 6)\\=120+12+336\\=468

So, this can be done in 468 ways.

7 0
3 years ago
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