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Thepotemich [5.8K]

3 years ago

13

19. PLEASE HELP ME

1 answer:

Licemer1 [7]3 years ago

8 0

Answer:

D. y= -1/5x2, y= -1/3x2, y= -7x2

Step-by-step explanation:

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The boundary of a lamina consists of the semicircles y = 1 − x2 and y = 16 − x2 together with the portions of the x-axis that jo

oksano4ka [1.4K]

Answer:

Required center of mass $(\bar{x},\bar{y})=(\frac{2}{\pi},0)$

Step-by-step explanation:

Given semcircles are,

$y=\sqrt{1-x^2}, y=\sqrt{16-x^2}$ whose radious are 1 and 4 respectively.

To find center of mass, $(\bar{x},\bar{y})$ , let density at any point is $\rho$ and distance from the origin is r be such that,

$\rho=\frac{k}{r}$ where k is a constant.

Mass of the lamina=m= $\int\int_{D}\rho dA$ where A is the total region and D is curves.

then,

$m=\int\int_{D}\rho dA=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}rdrd\theta=k\int_{}^{}(4-1)d\theta=3\pi k$

Now, x-coordinate of center of mass is $\bar{y}=\frac{M_x}{m}$ . in polar coordinate $y=r\sin\theta$

$\therefore M_x=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA$

$=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\sin\theta)rdrd\theta$

$=k\int_{0}^{\pi}\int_{1}^{4}r\sin\thetadrd\theta$

$=3k\int_{0}^{\pi}\sin\theta d\theta$

$=3k\big[-\cos\theta\big]_{0}^{\pi}$

$=3k\big[-\cos\pi+\cos 0\big]$

$=6k$

Then, $\bar{y}=\frac{M_x}{m}=\frac{2}{\pi}$

y-coordinate of center of mass is $\bar{x}=\frac{M_y}{m}$ . in polar coordinate $x=r\cos\theta$

$\therefore M_y=\int_{0}^{\pi}\int_{1}^{4}x\rho(x,y)dA$

$=\int_{0}^{\pi}\int_{1}^{4}\frac{k}{r}(r)\cos\theta)rdrd\theta$

$=k\int_{0}^{\pi}\int_{1}^{4}r\cos\theta drd\theta$

$=3k\int_{0}^{\pi}\cos\theta d\theta$

$=3k\big[\sin\theta\big]_{0}^{\pi}$

$=3k\big[\sin\pi-\sin 0\big]$

$=0$

Then, $\bar{x}=\frac{M_y}{m}=0$

Hence center of mass $(\bar{x},\bar{y})=(\frac{2}{\pi},0)$

3 0

2 years ago

Having a hard time with this one.

Vladimir79 [104]

answer for this question is 1/16

3 0

2 years ago

Graph the function for the given domain.<br><br> y = x2 − 4 D:{−2, −1, 0, 1, 2}

netineya [11]

Answer:

HOPING THIS HELPED YOU! MARK ME 5\

Step-by-step explanation:

8 0

2 years ago

I’ll click the heart please help

Pavlova-9 [17]

Answer:

The answer is just 4

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Grade 8 Mathematics level 3

ollegr [7]

The value of x in the given equation [ √( 1 + (25/144) ) = 1 + (x/12) ] is 5.

<h3>What is an Equation?</h3>

An equation is simply a mathematical formula that expresses the equality of two expressions, using the equals sign as a connection between them.

Given that;

√( 1 + (25/144) ) = 1 + (x/12)

Find the value of x.

First, we square both sides

√( 1 + (25/144) ) = 1 + (x/12)

(√( 1 + (25/144) ))² = (1 + (x/12))²

1 + (25/144) = 1 + ( x²/144)

Collect like terms

1 - 1 + (25/144) = ( x²/144)

25/144 = x²/144

We cross multiply

25 × 144 = x² × 144

Multiply each sides by 1/144

x² = 25

x = √25

x = 5

Therefore, the value of x in the given equation [ √( 1 + (25/144) ) = 1 + (x/12) ] is 5.

Learn more about equations here: brainly.com/question/14686792

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6 0

2 years ago