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Setler79 [48]
2 years ago
8

-x+y=1 -6x+3y=-12 Solve

Mathematics
1 answer:
Allisa [31]2 years ago
4 0

Answer:

-x = -y + 1

x = 0.5y + 2

Step-by-step explanation:

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A professor wants to award prizes for 1st, 2nd, 3rd, 4th and 5th in the class of 30. In how many ways can the prizes be awarded
aniked [119]

Answer:

Selection =  17100720\ ways

Step-by-step explanation:

Given

Students = 30

Positions = 5 i.e. first to fifth

Required

Determine number of selection

1st position = Any of the 30 students

2nd position = Any of the 29 students

3rd position = Any of the 28 students

4th position = Any of the 27 students

5th position = Any of the 26 students

Number of selection is then calculated as:

Selection =  30 * 29 * 28 * 27 * 26

Selection =  17100720\ ways

8 0
3 years ago
There are 92 students in a chemistry class. The instructor must choose two students at random. Students in a Chemistry Class Aca
Sergio039 [100]

Answer:

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability that a sophomore non-Chemistry major

Out of 92 students, 9 are non-chemistry major sophomores. So

P(A) = \frac{9}{92}

Then a junior non-Chemistry major are chosen at random.

Now, there are 91 students(1 has been chosen), of which 10 are non-chemistry major juniors. So

P(B) = \frac{10}{91}

What is the probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random

P = P(A)*P(B) = \frac{9}{92}*\frac{10}{91} = \frac{9*10}{92*91} = 0.0108

0.0108 = 1.08% probability that a sophomore non-Chemistry major and then a junior non-Chemistry major are chosen at random.

8 0
3 years ago
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