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3 years ago

15

If x=-2 and y=6 is a solution of equation 3ax+2by=6, then find the value of b

1 answer:

lana66690 [7]3 years ago

7 0

$\text{Substitute the values of x and y to the equation}\\\\x=-2,\ y=6,\ 3ax+2by=6\\\\3a(-2)+2b(6)=6\\\\-6a+12b=6\qquad|\text{add 6a to both sides}\\\\12b=6a+6\qquad|\text{divide both sides by 12}\\\\b=\dfrac{6a}{12}+\dfrac{6}{12}\\\\\boxed{b=\dfrac{1}{2}a+\dfrac{1}{2}}$

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Ad libitum [116K]

Answer:

5.26%

Step-by-step explanation:

Danielle measured the the mass at 40grams. ,Compared to 38 grams, there is a percentage increase.

Old Value = 38grams, New Value = 40grams

%Increase = 40-38/38 × 100%

%Increase = 5.26%

8 0

3 years ago

Find the perimeter of the polygon.

wel

Answer:

A. 25 cm

Step-by-step explanation:

Perimeter of a polygon = the sum of all sides of the polygon

Therefore,

Perimeter of the given polygon = 5 + 6 + 8 + 6

Perimeter = 25 cm

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3 years ago

Find the solutions to x2 = 24.

iren [92.7K]

Answer:

x = ± 2 $\sqrt{6}$

Step-by-step explanation:

Given

x² = 24 ( take the square root of both sides )

x = ± $\sqrt{24}$ = ± $\sqrt{4(6)}$ = ± $\sqrt{4}$ × $\sqrt{6}$ = ± 2 $\sqrt{6}$

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3 years ago

Evaluate the following integral over the specified region. Assume (r comma theta )(r,θ) are polar coordinates. ModifyingBelow In

topjm [15]

Answer:

Step-by-step explanation:

We have to integrate the function

$16+x^2+y^2$ over the region

$1\leq r\leq 3\\0\leq \theta \leq \pi$

Let us convert into polar coordinates

x=cost : y = sint

Then we get dxdy = rdr dt

So we get the integral as

$\int \int _R (16+x^2+y^2)^2 dxdy\\= \int\limits^3_0 \int\limits^\pi_0( {16+r^2}^2) (r)drdt\\ =(t) (\frac{(16+r^2)^3}{6}$

Substitute the limits to get

Answer

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3 years ago

The length of a rectangle exceeds its width by 3 inches. The area of the rectangle is 70

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Answer:

70= (x+3)

Step-by-step explanation:

the length of the rectangle its width by 3 inches, if the width is x,the length will be x+3. so A=LW= 70

To find= 70= (x+3)x

x= 7 or -10

3 0

3 years ago