The system of equations to determine the number of adult tickets, a, and the number of student tickets, s, the drama club sold is a + s = 1500; 12a + 6s = 16,200. 300 students attended the play.
<h3>Simultaneous equation</h3>
- number of adult tickets = a
- number of student tickets = s
The system of equation:
a + s = 1500
a + s = 150012a + 6s = 16,200
From equation (1)
a = 1500 - s
Substitute into (2)
12a + 6s = 16,200
12(1500 - s) + 6s = 16,200
18,000 - 12s + 6s = 16200
- 12s + 6s = 16200 - 18,000
-6s = -1800
s = -1800 / -6
s = 300
Substitute s = 300 into (1)
a + s = 1500
a + 300 = 1500
a = 1500 - 300
a = 1200
Therefore, there are 300 students and 1200 adults at the play respectively.
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In a parallelogram diagonals bisect each other,
=>AT=TX=>4y-2=14=>4y=14+2=>4y =16=>y=16/4=4
And ZT=TY=>2x+12=6x-12
=>12+12=6x-2x
=>24=4x
=>24/4=X
=>6=X
Hope this helps u...!!!
The Answer Is D. The Amount Owed At Various Times
Answer:
The negation to the given statement "At least one gift in the bag is wrapped - true" is "
At least one gift in the bag is not wrapped" - False
-
At least one gift in the bag is not wrapped - False
-
Not every gift in the bag is wrapped-True
- Every gift in the bag is wrapped-False
- None of the gifts in the bag are wrapped-False
Step-by-step explanation:
Given statement is At least one gift in the bag is wrapped is true
The negation to the given statement is "
At least one gift in the bag is not wrapped" - False
<u>To determine whether the statement is a negation of the given statement is True or False :</u>
<h3>
At least one gift in the bag is not wrapped - False
</h3><h3>
Not every gift in the bag is wrapped-True </h3><h3>
Every gift in the bag is wrapped-False
</h3><h3>
None of the gifts in the bag are wrapped-False</h3>
