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Luba_88 [7]
2 years ago
9

What is p(b)? what is p(a^c)

Mathematics
1 answer:
pickupchik [31]2 years ago
4 0

Answer: P(B)= 15 P(A^c)

Step-by-step explanation:

Multiply the first one then the second one multiply and then do to the 2nd power

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Elle decreased her monthly budget from $250 to $200. Calculate the percent decrease
kirill [66]
Formula for finding percent change (increase or decrease) is amount of the change divided by the original amount.

Here, the amount of the change is 50 and the original amount is 250.

50/250= 0.2

Multiply by 100 to get percent.

20% decrease (because budget went down)
6 0
3 years ago
I need help again help me pllsssssss
notka56 [123]

Answer: you end up at (2,2)

Step-by-step explanation:

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3 years ago
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A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Selma uses a jogging trail that runs through a park near her home. The trail is a loop that is 3/4 of a mile long. On Monday, Se
KIM [24]
(3/4) / (1/6) =
3/4 * 6/1 =
18/4 =
4.5 miles per hr <==
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Graph the equation 8x-4y=56 then, trace the graph to find the missing value in the coordinate pairs below
Marysya12 [62]
Just look at it this way do 8(1) instead of x and graph that on the x axis
then do 4(1)instead of y and graph on the y axis then figure out which numbers you need to keep inputting until you reach 56 on the graph.
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3 years ago
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