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pantera1 [17]
3 years ago
6

Jose had an assignment to classify mixtures he found around his home. As he started exploring the house, he recalled that mixtur

es are defined by the size and behavior of the particles in them. He found some buckets of paint in the garage. What kind of mixture can paint be classified as?
a
colloid
b
solution
c
solvent
d
suspension
Chemistry
1 answer:
mash [69]3 years ago
4 0

Answer:

a  colloid

Explanation:

Paint is classified a colloid

A colloid is a homogenous of two phases which are the dispersed phase and the dispersion medium.

The dispersed phase is analogous to the solute of the true solution while the dispersion medium is analogous to the solvent.

  • The particles of colloids are larger than those found in a solution.
  • Their particles do not settle on standing
  • Their particles pass through ordinary filter paper
  • Their particles do not pass through permeable membranes
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Answer:

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Ethylene produced by fermentation has a specific gravity of 0.787 at 25 degree Celsius. What is the volume of 125g of ethanol at
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<u>Answer:</u> The volume of given amount of ethanol at this temperature is 159.44 mL

<u>Explanation:</u>

Specific gravity is given by the formula:

\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}

We are given:

Density of water = 0.997 g/mL

Specific gravity of ethanol = 0.787

Putting values in above equation, we get:

0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL

Density is defined as the ratio of mass and volume of a substance.

\text{Density}=\frac{\text{Mass}}{\text{Volume}} ......(1)

Given values:

Mass of ethanol = 125 g

Density of ethanol = 0.784 g/mL

Putting values in equation 1, we get:

\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL

Hence, the volume of given amount of ethanol at this temperature is 159.44 mL

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Answer:

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