All categories

2 years ago

2. Reaction between magnesium & sulphur

Chemistry

2 answers:

Svetradugi [14.3K]2 years ago

7 0

Answer:

magnesium suphide or magnesium suphate

Explanation:

diamong [38]2 years ago

4 0

Answer:

Mg combines with SO2 to create MgO and S. When magnesium ribbon is burned in a sulphur dioxide-rich environment, the element magnesium reacts with the oxygen atom in the sulphur dioxide and burns constantly. This is a redox reaction (oxidation-reduction). Mg is a reducing agent, while SO2 is an oxidising agent.

You might be interested in

Tails of phospholipids that don't like water

densk [106]

Those tails are called hydrophobic. You can note the etymology: hydro= water, phobi = fear, aversion, dislike.

Phospholipds' tail is a long non polar chain, made of Carbon and Hydorgens, that rejects water (a polar solvent) and is attracted to non-polar compounds (oil for example). That is why that tails can atract dirt.

3 0

3 years ago

Hospital patients are administered oxygen from an pressurized

VashaNatasha [74]

Answer:

32000atm

Explanation:

Using Boyle's law equation;

P1V1 = P2V2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (

V2 = final volume (L)

According to the question below:

P1 = 160.0 atm

P2 = 3.0 atm

V1 = 600L

V2 = ?

Using P1V1 = P2V2

160 × 600 = 3 × V2

96000 = 3V2

V2 = 96000/3

V2 = 32000atm

5 0

2 years ago

The standard emf for the cell using the overall cell reaction below is +2.20 V:

ANEK [815]

Answer:

emf generated by cell is 2.32 V

Explanation:

Oxidation: $2Al-6e^{-}\rightarrow 2Al^{3+}$

Reduction: $3I_{2}+6e^{-}\rightarrow 6I^{-}$

---------------------------------------------------------------------------------

Overall: $2Al+3I_{2}\rightarrow 2Al^{3+}+6I^{-}$

Nernst equation for this cell reaction at $25^{0}\textrm{C}$ -

$E_{cell}=E_{cell}^{0}-\frac{0.059}{n}log{[Al^{3+}]^{2}[I^{-}]^{6}}$

where n is number of electrons exchanged during cell reaction, $E_{cell}^{0}$ is standard cell emf , $E_{cell}$ is cell emf , $[Al^{3+}]$ is concentration of $Al^{3+}$ and $[Cl^{-}]$ is concentration of $Cl^{-}$

Plug in all the given values in the above equation -

$E_{cell}=2.20-\frac{0.059}{6}log[(4.5\times 10^{-3})^{2}\times (0.15)^{6}]V$

So, $E_{cell}=2.32V$

3 0

2 years ago

PLEASE HELP ASAP! BRAINLIEST WILL BE GIVEN PLEASE HELP!

inessss [21]

I think it is D I'm not positive

5 0

3 years ago

Read 2 more answers

Reaction is

-Dominant- [34]

According to the task, you are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C
<span>The you go :
</span> $CO2(g) + C(s) \ \textless \ =\ \textgreater \ 2CO(g)$

n1 n2 0
-x -x +2x
$n1-x n2-x 2x Kp=P^2 (CO)/Pco2$
After that you have to use the formula $PV=nRT$
$Kp=(2x)^2/n1-x$
Then you have to solve x, and for that you have to use <span>RT/V
And to find total values:</span> $P(total)=n(total)*R*T/V$
I am absolutely sure that this would be helpful for you.

7 0

3 years ago

2. Reaction between magnesium & sulphur​

2. Reaction between magnesium & sulphur