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3 years ago

Can someone please help mee.

Mathematics

1 answer:

Ahat [919]3 years ago

4 0

Answer:

$\displaystyle y$

Step-by-step explanation:

<u>Graph of an inequality</u>

The graph represented in the image is a line and we have two clear points through which the line passes.

Those points are (0,1) and (5,0).

The equation of a line can have the slope-intercept form:

y=mx+b

Substituting the point (0,1):

1=0+b

b=1

Substituting the point (5,0):

0=m(5)+1

Solving for m:

$\displaystyle m=-\frac{1}{5}$

The equation of the line is:

$\displaystyle y=-\frac{1}{5}x+1$

The origin belongs to the solution if we substitute (0,0) the inequality should stand:

0<1

Or:

0≤1

Since the line is dashed, the boundary line is not part of the solution

Thus the inequality is:

$\boxed{\displaystyle y$

Option D.

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Y + 1 1/6 = 7 5/6 what is Y

AfilCa [17]

Answer:

6 $\frac{2}{3}$

Step-by-step explanation:

y + 1 $\frac{1}{6}$ = 7 $\frac{5}{6}$

y + $\frac{7}{6}$ = $\frac{47}{6}$

y = 40/6 = 20/3 = 6 $\frac{2}{3}$

3 0

3 years ago

In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe

andre [41]

SOLUTIONS

Given: Assume y is the population

$\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}$

The town grow at the rate of 30 people per year.

$y=kt+14000$ $y=30t+14000$

(A) The population predicted to be in 2030 will be

$\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}$

(B) so when y = 15000, find t

$\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}$

3 0

1 year ago

Which sentence can represent the inequality 2.4 (6.2 minus x) greater-than negative 4.5?

-BARSIC- [3]

Answer: Choice B

Two and four tenths multiplied by the difference of six and two tenths and a number is more than negative four and five tenths.

======================================================

Explanation:

2.4 = 2 + 0.4

2.4 = 2 and 4/10

2.4 = 2 and 4 tenths

2.4 = two and four tenths

-------------------

Through similar reasoning,

6.2 = six and two tenths

And also,

-4.5 = negative four and five tenths

---------------------

Notice how 6.2 - x translates into "difference of six and two tenths and a number"

We then multiply that by 2.4, aka two and four tenths.

So that's how we get the phrasing "Two and four tenths multiplied by the difference of six and two tenths and a number"

All of this is greater than -4.5 aka negative four and five tenths.

This points us to Choice B as the final answer.

7 0

3 years ago

Read 2 more answers

A local drive in theatre sells entrance tickets for cars on weekend nights. At compacity, the drive in can hold 72 cars. The fun

Paraphin [41]

All positive integers less than or equal to 72<span />

4 0

3 years ago

Read 2 more answers

Dylan Rieder is a statistics student investigating whether athletes have better balance than non-athletes for a thesis project.

Kobotan [32]

Answer:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

$p_v =P(t_{75}$

Comparing the p value with a significance level for example $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't say that the population mean for the athletes is significantly lower than the population mean for non athletes.

Step-by-step explanation:

Data given and notation

$\bar X_{A}=3.7$ represent the mean for athletes

$\bar X_{NA}=4.1$ represent the mean for non athletes

$s_{A}=1.1$ represent the sample standard deviation for athletes

$s_{NA}=1.3$ represent the sample standard deviation for non athletes

$n_{A}=32$ sample size for the group 2

$n_{NA}=45$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the population mean for athletes is lower than the population mean for non athletes, the system of hypothesis would be:

Null hypothesis: $\mu_{A}-\mu_{NA}\geq 0$

Alternative hypothesis: $\mu_{A} - \mu_{NA}< 0$

We don't have the population standard deviation's, we can apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{A}-\bar X_{NA})-\Delta}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{NA}}{n_{NA}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(3.7-4.1)-0}{\sqrt{\frac{1.1^2}{32}+\frac{1.3^2}{45}}}}=-1.457$

P value

We need to find first the degrees of freedom given by:

$df=n_A +n_{NA}-2=32+45-2=75$

Since is a one left tailed test the p value would be:

$p_v =P(t_{75}$

5 0

3 years ago