Ms. Burke invested $53,650, part at 10.5% and the rest at 12%. If the income from the 10.5% investment is one third of that from
the 12% investment, how much did she invest at each rate?
1 answer:
Answer:
$14,800 at 10.5%
$38,850 at 12%
Step-by-step explanation:
Investment at 10.5% (x):
(0.12[$53,650 - x])/0.105x = 3
$6,438 - 0.12x = 0.315x
0.435x = $6,438
x = $14,800
Investment at 12%:
= $53,650 - $14,800
= $38,850
Answer: Investments: @ 10.5%, $14,800; @ 12%, $38,850
Proof: (income from 1st is 1/3 that of the income from the 2nd):
= (0.105[$14,800])/(0.12[$38,850])
= $1,554/$4,662
= 1/3
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