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2 years ago

A pair of equations is shown below.

Mathematics

1 answer:

maksim [4K]2 years ago

8 0

Answer:

4,3

Step-by-step explanation:

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If 3/4 are tulips, and there are 2/3 that are red tulips, what fraction of the tulips a re yellow.

Alex_Xolod [135]

I hope this helps you! it's relatively straightforward but if you need more explanations, don't hesitate to ask!

7 0

2 years ago

Simplify the expression using the rules for

german

Step-by-step explanation:

(a×b^-3×c^-3)⁵ / (a^-3×b⁴×c⁴)^-5

let's look at the numerator (the top) first :

a⁵×b^-15×c^-15

and now the denominator (the bottom) :

a¹⁵×b^-20×c^-20

both divided are (due to the commutative rules of multiplication we can split this first into the parts of the individual variables, and then multiply them all with each other) :

a⁵/a¹⁵ = 1/a¹⁰

b^-15 / b^-20 = b^(-15 ‐ -20) = b⁵

c^-15 / c^-20 = c⁵

so we get as result :

b⁵c⁵/a¹⁰

6 0

1 year ago

Read 2 more answers

Suppose that 23 inches of wire costs 92 cents. At the same rate, how much (in cents) will 19 inches of wire cost?

REY [17]

Answer:

76 cents

Step-by-step explanation:

23 inches = 92 cents

1 inches = 92 ÷ 23

= 4 cents

19 inches = 19 × 4

= 76

5 0

1 year ago

|b|+b^3;b=-2 evaluate the expression

saveliy_v [14]

Answer:

-6

Step-by-step explanation:

$| - 2| = 2 \\ {( - 2)}^{3} = ( - 2)( - 2)( - 2) = ( - 8) \\ \\ | - 2 | + {( - 2)}^{3 } = 2 - 8 = - 6$

5 0

2 years ago

A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s

Umnica [9.8K]

Answer:

88.51 is the minimum score needed to receive a grade of A.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

We have to find the value of x such that the probability is 0.0793.

$P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793$

$= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793$

$=P( z \leq \displaystyle\frac{x - 73}{11})=0.9207$

Calculation the value from standard normal z table, we have,

$P(z \leq 1.410) = 0.9207$

$\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51$

Hence, 88.51 is the minimum score needed to receive a grade of A.

3 0

2 years ago