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Reptile [31]
3 years ago
6

Using a pair of compass only construct a triangle ABC such that AB=9cm, angle BAC=60° and angle ABC=45°

Mathematics
1 answer:
Leto [7]3 years ago
6 0

Answer:

AC=5.4 BC=7.2

Step-by-step explanation

180-60-45=75 degree

9/75=AC/45=BC/60

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-7=2+ w<br><br> Help please
ziro4ka [17]

Answer:

w= -9 :)

Step-by-step explanation:

5 0
3 years ago
YZ has endpoints Y(0,5) and Z (12,3). Find the length of YZ to the nearest tenth.
Alex Ar [27]
Using the formula;
 d(Y, Z) =\sqrt{(xZ - xY)^2 + (yZ - yY)^2

You should get 12.1655 or 12.2 units.

Hope this helps you with Coordinate Solving!

4 0
4 years ago
Read 2 more answers
A zookeeper predicted the weight of a new baby elephant to be 230 pounds when I was born the elephant actually weigh 262 pounds
insens350 [35]

Answer:

13.9%

Step-by-step explanation:

Given data

Expected weight = 230 pounds

Actual weight= 262 pounds

Required

The percent error

Error= Actaul- expected/ expected *100

Error= 262-230/230*100

Error=32/230*100

Error=0.139*100

Error=13.9%

Hence the error is 13.9%

5 0
3 years ago
cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0
Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder=2\pi rh

Area of circular base=Area of circular top=\pi r^2

Total cost,C(r)=0.02\times 2\pi rh+2\pi r^2\times 0.07

Volume of cylinder,V=\pi r^2 h

200=\pi r^2 h

h=\frac{200}{\pi r^2}

Substitute the value of h

C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07

C(r)=\frac{8}{r}+0.14\pi r^2

Differentiate w.r.t r

C'(r)=-\frac{8}{r^2}+0.28\pi r

C'(r)=0

-\frac{8}{r^2}+0.28\pi r=0

0.28\pi r=\frac{8}{r^2}

r^3=\frac{8}{0.28\pi}=9.095

r=(9.095)^{\frac{1}{3}}=2.09

Again, differentiate w.r.t r

C''(r)=\frac{16}{r^3}+0.28\pi

Substitute the value of r

C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0

Therefore,the product cost is minimum at r=2.09

h=\frac{200}{\pi (2.09)^2}=14.57

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0
3 years ago
a pipe is leaking at 1.5 cups per day. about how many gallons per week is the pipe leaking? (HINT : 1 gallon = 16 Oz) 
Basile [38]
.65625 gallons per week
tht ur answer
3 0
3 years ago
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