3) 3(8b + 3)
4) 57
I’m pretty sure that this is the answer
Answer:
I don't know the value of either, could you add more information?
Step-by-step explanation:
I'd be glad to help.
Answer:what do you mean
Step-by-step explanation:
It’s option B. Because that’s the try statement.
Let w be the width and l the length of the rectangle.
Then:
![\frac{l}{w}= \frac{1+\sqrt5}{2} \text{ and }lw=104](https://tex.z-dn.net/?f=%20%5Cfrac%7Bl%7D%7Bw%7D%3D%20%5Cfrac%7B1%2B%5Csqrt5%7D%7B2%7D%20%20%5Ctext%7B%20and%20%7Dlw%3D104)
Solving the above system we get:
![l= \frac{1+\sqrt5}{2}w\\= \frac{1+\sqrt5}{2}\frac{104}{l}](https://tex.z-dn.net/?f=%20l%3D%20%5Cfrac%7B1%2B%5Csqrt5%7D%7B2%7Dw%5C%5C%3D%20%5Cfrac%7B1%2B%5Csqrt5%7D%7B2%7D%5Cfrac%7B104%7D%7Bl%7D)
Therefore:
![l^2=\frac{1+\sqrt5}{2}104](https://tex.z-dn.net/?f=l%5E2%3D%5Cfrac%7B1%2B%5Csqrt5%7D%7B2%7D104)
then
![l=13](https://tex.z-dn.net/?f=l%3D13%20)
,which is the length,
And then the width