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3 years ago

Given a bag of 5 blue, 3 green, and 8 red marbles.. What is the probability of picking a blue

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

6 0

$b = 5, \: g = 3, \: r = 8$

$total = 5 + 3 + 8 = 16$

$p(b) = \frac{5}{16}$

$p(g |without \: replacement|) = \frac{3}{16 - 1} = \frac{3}{15} = \frac{1}{5} \\$

$p(b \: and \: g) = \frac{5}{16} \times \frac{1}{5} = \frac{1}{16}$

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How many of the first 15 positive integers can be written as the sum of three squares?

Jlenok [28]

Answer

no number from the following list can be expressed as the sum of three squares: 7, 15, 23, 31, 39, 47, ect... so only once

Step-by-step explanation:

nono dont touch me there this is my nono square

3 0

2 years ago

Which expression is equivalent to (4g3h2k4)3

RSB [31]

Answer:

d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

Explanation

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{9-3}h^{6-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

3 0

2 years ago

A-b.a+b= giúp mình nhé

lilavasa [31]

Step-by-step explanation:

Did you mean:

= (a - b)(a + b)

= a.a + b.a - b.a - b.b

= a² + ba - ba - b²

= a² - b²

3 0

2 years ago

DOES ANYONE UNDERTAND THIS? IF SO PLEASE HELP

Nana76 [90]

The sides must be equal otherwise BC and AD wouldn't be parallel. So
12x-6 = 2x+7
10x = 13
x = 13/10 = 1.3

8 0

3 years ago

Addison's Cafe offers two kinds of espresso: single-shot and double-shot. Yesterday afternoon, the cafe sold 70 espressos in all

Valentin [98]

Answer:

The number of single-shot espressos sold by the cafe was 49.

Step-by-step explanation:

It is provided that Addison's Cafe offers two kinds of espresso: single-shot and double-shot.

Total number of espressos sold by the cafe yesterday afternoon was,

N = 70

The proportion of single-shot espresso sold was, p = 0.70.

Let X = number of single-shot espressos sold.

Compute the number of single-shot espressos sold by the cafe as follows:

$E(X)=N\times p$

$=70\times 0.70\\=49$

Thus, the number of single-shot espressos sold by the cafe was 49.

6 0

3 years ago