<span> binomdist with n = 3, p = 0.82, q = 1-0.82 = 0.18
P[≥2] = P[2] + P[3] = 3c2 *0.82^2*0.18 + 0.82^3 ≈ 91%
hope it helps
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I hope this helps you
Ax+By=C
By=C-Ax
y=C/B-A/Bx
m= -A/B
E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15
Bayes' theorem is transforming preceding probabilities into succeeding probabilities. It is based on the principle of conditional probability. Conditional probability is the possibility that an event will occur because it is dependent on another event.
P(F|E)=P(E and F)÷P(E)
It is given that P(E)=0.3,P(F|E)=0.5
Using Bayes' formula,
P(F|E)=P(E and F)÷P(E)
Rearranging the formula,
⇒P(E and F)=P(F|E)×P(E)
Substituting the given values in the formula, we get
⇒P(E and F)=0.5×0.3
⇒P(E and F)=0.15
∴The correct answer is 0.15.
If, E and F are two events and that P(E)=0.3 and P(F|E)=0.5. Thus, P(E and F)=0.15.
Learn more about Bayes' theorem on
brainly.com/question/17010130
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Let
represent Jose's drived distance and
represent Rob's.
So what you need to do is to solve the equation:
So Jose drove for
6 hours before Rob caught him.
