In general 2^n is the number of pieces of information n bits can store.
(a) Antonio can use the formula 2^n-1 to indicate the maximum size of numbers an n-bit word can store.
(b) for a 16-bit system, the maximum number of keys Millie can collect is 2^(16)-1 = 65536-1=65535
(c) For a 14 byte program, there are 14*8=112 bits.
Answer:
The number of pages that will make the cost of printing equal for both options is 500
Step-by-step explanation:
Please, kindly see the attached file for explanation
Answer=18,482 students
17113 x
_______=_____
100% 108%
Cross multiply
100x=<span>1848204
divide both sides by 100
x=18482.04
Round to the nearest whole number
x=18,482 students</span>
If that is 6-3(log2n)=0 then how you would go about solving it is by looking at log2n like x. In this case, for 6-3x=0, x would have to =2. So log2n has to =2. If log2n=2 and we assume that the base is 10 (because if there is no written base on a log then it is 10) then we need to rewrite the log to exponential form. Rewritten it's 10^2=2n. 100=2n, divide both sides by 2 and you get n=50.
Answer:
Step-by-step explanation:
16x^2 + 9 = 25
16x^2 = 16
x^2 = 1
x = 1, -1