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kolezko [41]
3 years ago
10

hayden solved this equation using the steps shown. |x-3|=4. step 1: x-3=4.step 2: x-3+3=4+3. solution: x=7. based on the definit

ion of absolute value, what additional step should hayden do to determine the complete solution to the equation?
Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

step 3: x - 3 = -4

step 4: x - 3 + 3 = -4 + 3

second solution: x = -1

Step-by-step explanation:

The definition of absolute value is:

|x| = y -> x = y or x = -y

Hayden did only the first part:

|x-3|=4 -> x-3 = 4

And he found the first solution: x = 7.

But know he needs to do the second part, that is, make the right side equal the negative of the left side:

step 3: x - 3 = -4

step 4: x - 3 + 3 = -4 + 3

second solution: x = -1

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Answer:

x² - 3x - 10 = (x - 5) (x + 2)

x² - 3x - 18 = (x + 3) (x - 6)

Step-by-step explanation:

<u>x² - 3x - 10</u>

x² + 2x - 5x - 10

x(x + 2) - 5(x + 2)

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How do you solve the equation 5x= 1 2/3
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Val walks 2 3/5 miles each day. Bill runs 10 miles once every 4 days. In 4days, who covers the greater distance.
Brilliant_brown [7]
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Read 2 more answers
Out of the 400 students in a final year in secondary school, 300 are offering biology and 190 are offering chemistry. I) how man
iren2701 [21]

Answer:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

= 160 students

II) how many students are offering at least one biology and chemistry?

= 330 students

Step-by-step explanation:

I) how many student are offering both subject , if only 70 students are offering neither biology nor chemistry?

Total number of student n ( B ∪ C) = 400

Students offering biology n(B) = 300

Students offering chemistry n(C) = 190

Students not offering biology nor chemistry = 70

Students offering both biology and chemistry n ( B ∩ C) = ??

n ( B ∪ C) - Students neither offering biology nor chemistry = n(B ) + n ( C ) - n ( B ∩ C)

400 - 70 = 300 + 190 - n ( B ∩ C)

330 = 490 - n ( B ∩ C)

n ( B ∩ C) = 490 - 330

n ( B ∩ C) = 160

Therefore, students offering both Biology and Chemistry are 160 students.

II) how many students are offering at least one biology and chemistry?

n(B' ) + n ( C') + n ( B ∩ C)

n(B') = Students offering biology only

= n(B) - n ( B ∩ C)

= 300 - 160 = 140

n(C') = Students offering chemistry only

n(C) - n ( B ∩ C)

= 190 - 160

= 30

(300 - 160) + (190 - 160) + 160

140 + 30 + 160

= 330 students

4 0
3 years ago
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