1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolezko [41]
3 years ago
10

hayden solved this equation using the steps shown. |x-3|=4. step 1: x-3=4.step 2: x-3+3=4+3. solution: x=7. based on the definit

ion of absolute value, what additional step should hayden do to determine the complete solution to the equation?
Mathematics
1 answer:
PolarNik [594]3 years ago
8 0

Answer:

step 3: x - 3 = -4

step 4: x - 3 + 3 = -4 + 3

second solution: x = -1

Step-by-step explanation:

The definition of absolute value is:

|x| = y -> x = y or x = -y

Hayden did only the first part:

|x-3|=4 -> x-3 = 4

And he found the first solution: x = 7.

But know he needs to do the second part, that is, make the right side equal the negative of the left side:

step 3: x - 3 = -4

step 4: x - 3 + 3 = -4 + 3

second solution: x = -1

You might be interested in
Does the equation 6x + 35 = -6x - 35 have no, one, or infinite solutions?
fenix001 [56]

Answer:

The equation has one solution.

Step-by-step explanation:

6x + 35 = -6x - 35

subtract 6x from both sides of the equation

35 = -35 - 12x

add 35 to both sides of the equation

70 = -12x

divide -12x on both sides of the equation

x = 5.833333333

6 0
2 years ago
Helpppppppppppppppppppppppp
motikmotik

Answer:

1A, 2C, 3X, 4A, 5B, 6W, 7X

Step-by-step explanation:

Im not sure about these answers, can you have the same letter for a different number?

5 0
3 years ago
To get from point A to point B you must avoid walking
Nikitich [7]

p

the rigth awnser is 41 meaters east to were

Step-by-step explanation:

possible to walk through the

7 0
3 years ago
I'm lazzzzzzzzy pls answer asap
elena-s [515]
The second one because you times the exponents together
8 0
3 years ago
Read 2 more answers
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
Other questions:
  • 20baskets into 4minutes
    15·1 answer
  • What is the value of x
    13·1 answer
  • A manufacturer inspects 400 personal video players that 397 of the have no defects. The manufacturer sent a shipment of 1,500 vi
    14·1 answer
  • I will mark as brainliest, thank you
    9·2 answers
  • What is 3/8 plus 1/12
    6·1 answer
  • A florist can order roses in bunches of 12 and lillies in bunches of 8 if she ordered 100 of each flower how many bunches of eac
    11·2 answers
  • Evaluate seven pi without a calculator
    10·1 answer
  • Find the slope of the line that passes through (10,1) and (5,2) PLEASE DO A STEP BY STEP EXPLANATION i learn nothing from my tea
    13·2 answers
  • Solve the following system of equations graphically on the set of axes below. Y=-x+1 Y=1/4x+6
    15·1 answer
  • Mary saved her money
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!