A rectangular shape of dimension 95 m by 75 m is drawn to a scale of 1 cm to 10 m . Find the area of the drawing

Stels [109]

1420-1065 = 355 dollars. Lets find out how many percent 355 dollars are of the original prise. We divide them 355/1420= 0,25, we then say 0,25 * 100 = 25%

5 0

3 years ago

1- if angle A = 30, then its complementary is -- and its supplementary is

dezoksy [38]

1 - complementary = 90- 30 = 60

suplementary = 180- 30 = 150

2 - area = hb/2 = 360 = hb/2 = h = 72

3 - similar

4- see number 3

5 - asa, ssa, sas

6 - polygon that had all equal angle measures and sides (equiangular and equilateral)

7 - length x width = area so

240 / 24 = 10

8 - line

9 - triangle

10 - 180, as see in question 1

vote me brainliest ):>

5 0

3 years ago

A 555-mile, 5-hour plane trip was flown at two speeds. For the first part of the trip, the average speed was 105 mph. Then the t

Pepsi [2]

Answer:

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

Step-by-step explanation:

Given:

Total Distance = 555 mile

Total time = 5 hour

Let time taken to travel at 115 mph be t

So Time taken to travel at 105 mph will be equal to difference between Total time and time taken to travel at 115 mph.

Time taken to travel at 105 mph = $5-t$

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 115 mph = $115t$

Also;

Distance traveled in speed 105 mph will be equal to speed multiplied by time taken to travel at 105 mph.

Framing in equation form we get;

Distance traveled in 105 mph = $105(t-5) = 105t - 525$

Now Total Distance traveled is equal sum of Distance traveled in 115 mph and Distance traveled in speed 105 mph

$115t-(105t-525)=555\\\\115t-105t+525=555\\\\10t+525=555\\\\10t=555-525\\\\10t=30\\\\t=\frac{30}{10}=3$

Time taken to travel at 115 mph = 3 hrs.

Time taken to travel at 105 mph = $5-t=5-3=2\ hrs$

Now Distance traveled in 115 mph = $115t = 115 \times 3 = 345\ miles$

Distance traveled in 105 mph = $105(5-t) = 105(5-3)= 105\times 2 = 210\ miles$

Hence Distance traveled at speed 115 mph is 345 miles and Distance traveled at speed 105 mph is 210 miles.

6 0

3 years ago

Point M is the midpoint of AB. The coordinates of point A are (-7, 1) and the coordinates of M are (-4,1). What are the coordina

I am Lyosha [343]

Answer:

The coordinates of point B are : (-1, 1)

Step-by-step explanation:

$\frac{-7+x^{2} }{2} = -4\\\frac{1+y^{2} }{2} =1$ You multiply -4 by 2 which gives you -8 then you multiply 1 by 2 which gives 2.

Then you create the equations $-7 + x^{2} = -8\\1 + y^{2} = 2$ you substitute -7 for +7 and add 7 to -8 which gives -1 ( $x^{2}$ ) and subtract 1 from 2 which gives you 1 ( $y^{2}$ )