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Alex17521 [72]
2 years ago
13

What’s the quotent of -3/8 and -1/4

Mathematics
2 answers:
OLga [1]2 years ago
8 0
1.5

It needs to be 20 characters long so I’m just putting this so I can actually submit. The other guy already out the explanation so I’m proud of you and just tryna get points. Anyways the calculator is always available too if you need it
astra-53 [7]2 years ago
3 0

Answer:

1.5

Step-by-step explanation:

-3/8=-0.375

-1/4=-0.25

the negatives cancel each other out so it is 0.375/0.25

.25 goes into .375  1.5 times, so the answer is 1.5

Have a good day!

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If A is a 2 × 2 matrix, then A × I = <br> and I × A =
krok68 [10]

Since the multiplication between two matrices is not <em>commutative</em>, then \vec A\, \times\,\vec I \ne \vec I \,\times \,\vec A, regardless of the dimensions of \vec A.

<h3>Is the product of two matrices commutative?</h3>

In linear algebra, we define the product of two matrices as follows:

\vec C = \vec A \,\times \vec B, where \vec A \in \mathbb{R}_{m\times p}, \vec B \in \mathbb{R}_{p\times n} and \vec C \in \mathbb{R}_{m \times n}     (1)

Where each element of the matrix is equal to the following dot product:

c_{ij} = \left[\begin{array}{cccc}a_{i1}&a_{i2}&\ldots&a_{ip}\end{array}\right]\,\bullet\,\left[\begin{array}{ccc}b_{1j}\\b_{2j}\\\vdots\\b_{pj}\end{array}\right], where 1 ≤ i ≤ m and 1 ≤ j ≤ n.     (2)

Because of (2), we can infer that the product of two matrices, no matter what dimensions each matrix may have, is not <em>commutative</em> because of the nature and characteristics of the definition itself, which implies operating on a row of the <em>former</em> matrix and a column of the <em>latter</em> matrix.

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To learn more on matrices: brainly.com/question/9967572

#SPJ1

3 0
2 years ago
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